This paper revisits and corrects previous results on nonimmersions of real projective spaces using tmf, providing new proofs, filling gaps, and fully determining related tmf cohomology groups.
Contribution
It corrects and completes earlier nonimmersion results for RP^n using tmf, and determines specific tmf cohomology groups for product spaces.
Findings
01
Confirmed nonimmersion results for RP^n with n as small as 48
02
Filled a gap in the proof regarding axial maps and cohomology classes
03
Determined tmf^{8*}(RP^
imes RP^
) and tmf^*(CP^
imes CP^
) in positive dimensions
Abstract
In a 2002 paper, the authors and Bruner used the new spectrum tmf to obtain some new nonimmersions of real projective spaces. In this note, we complete/correct two oversights in that paper. The first is to note that in that paper a general nonimmersion result was stated which yielded new nonimmersions for RP^n with n as small as 48, and yet it was stated there that the first new result occurred when n=1536. Here we give a simple proof of those overlooked results. Secondly, we fill in a gap in the proof of the 2002 paper. There it was claimed that an axial map f must satisfy f^*(X)=X_1+X_2. We realized recently that this is not clear. However, here we show that it is true up multiplication by a unit in the appropriate ring, and so we retrieve all the nonimmersion results claimed in the original paper. Finally, we present a complete determination of tmf^{8*}(RP^\infty\timesβ¦
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Taxonomy
TopicsHomotopy and Cohomology in Algebraic Topology Β· Algebraic Geometry and Number Theory Β· Nonlinear Waves and Solitons
In a 2002 paper, the authors and Bruner used
the new spectrum tmf to obtain some new nonimmersions of real
projective spaces. In this note, we complete/correct two oversights
in that paper.
The first is to note that in that paper a general
nonimmersion result was stated which yielded new nonimmersions for RPn with
n as small
as 48, and yet it was stated there that the first new result occurred
when n=1536. Here we give a simple proof of those overlooked results.
Secondly, we fill in a gap in the proof of the 2002 paper. There it was
claimed that an axial map f must satisfy
fβ(X)=X1β+X2β. We realized recently that this is not clear.
However, here we show that it is true up multiplication by a unit
in the appropriate ring, and so we retrieve all the nonimmersion results
claimed in [6].
Finally, we present a complete determination
of tmf8β(RPβΓRPβ) and tmfβ(CPβΓCPβ) in positive
dimensions.
Key words and phrases:
immersion, projective space, elliptic cohomology
2000 Mathematics Subject Classification:
57R42, 55N20.
We thank Steve Wilson for causing us to take a look
at these matters.
1. Introduction
In [6], the authors and Bruner described a proof of the following theorem, along with some
additional nonimmersion results.
Theorem 1.1**.**
(\cite[cite][\@@bibrefBDM,1.1])* Assume that M is divisible by the smallest
2-power greater than or equal to h.*
β’
If Ξ±(M)=4hβ1, then P8M+8h+2 cannot be immersed in (ξ β)R16Mβ8h+10.
β’
If Ξ±(M)=4hβ2, then P8M+8hξ βR16Mβ8h+12.
Here and throughout, Ξ±(M) denotes the number of 1βs in the binary expansion of M, and Pn
denotes real projective space.
In [6], the theorem is followed by a comment that this is new provided Ξ±(M)β₯6, i.e., hβ₯2, and the
first new result occurs for P1536. In this note, we point out that 1.1 is valid when
h=1, and these results are new when M is even, including new nonimmersions of Pn for n as small as
56. A remark in [6, p.66] that the nonimmersions when h=1 were implied by earlier work of the authors
was incorrect.
Letting h=1 in 1.1, we have the following result.
Corollary 1.2**.**
a. If Ξ±(M)=3, then P8M+10ξ βR16M+2.
b. If Ξ±(M)=2, then P8M+8ξ βR16M+4.
Part (a) is new when M is even. It is 2 better than the previous best result, proved in [4], and the nonembedding result that it implies is also new, 1 better than the previous best, proved in [3].
In [7], a table of known nonimmersions, immersions, nonembeddings, and embeddings of Pn
is presented, arranged according to n=2i+d with 0β€d<2i and d<64. Part (a) enters the table with a new result
for d=58, applying first to P122.
If M is even, 1.2.b is new, 1 better than the previous best result, of [12], and the nonembedding
result implied is also new. It enters [7] at d=24 and 40, with a new result for Pn with n as small as 56. The result of 1.2.b with M=2i+1 was also proved very recently by Kitchloo and Wilson in [15]. This result for P2k+16,
2 better than the previous result of [4] and also new as a nonembedding, enters [7] at d=16, and applies for n as small as 48.
In Section 2, we present a self-contained proof of Corollary 1.2. The primary reason for doing this,
which amounts to a reproof of part of [6, 1.1], is
that the proof of the general case in [6] requires some extremely elaborate arguments
and calculations. Our proof here, which is just for the case h=1, is much more comprehensible.
The proof in [6] contained an oversight which we shall correct here. The argument there was that
an immersion of RPn in Rn+k implies existence of an axial map PnΓPm@>f>>Pm+k
for an appropriate value of m, and obtains a contradiction for certain n, m, and k by consideration of tmfβ(f). Here tmf is the spectrum of topological modular forms, which was discussed in [6]. A class Xβtmf8(Pn) was described, along with X1β=XΓ1 and X2β=1ΓX in
tmf8(PnΓPm). It was asserted that fβ(X)=X1β+X2β, and a contradiction obtained by showing
that, for certain values of the parameters, we might have Xβ=0 but (X1β+X2β)βξ =0.
We recently realized that it is conceivable that fβ(X) might contain other terms coming from tmf8(Pnβ§Pm).
In Section 3 (see Theorem 3.7) we perform a complete
calculation of tmfβ(PβΓPβ) in positive gradings divisible by 8,
and in Section 4 we use it to show that effectively fβ(X)=u(X1β+X2β), where u
is a unit in tmfβ(PβΓPβ), which enables us to retrieve
all the nonimmersions of [6].
In Section 5, we compute tmfβ(CPβΓCPβ) in positive gradings.
The original purpose of doing this was, prior to our obtaining the argument of Section 4,
to see whether we might mimic the argument of [2] and [8] to conclude that if f is an
axial map, then fβ(X) might necessarily equal u(X1ββX2β), where u is a unit in
tmfβ(CPΓCP). This approach to retrieving the nonimmersions of [6] did not yield
the desired result, but the later approach given in Section 4 did. Nevertheless
the nice result for tmfβ(CPβΓCPβ)
obtained in Theorem 5.19 should be of independent interest.
We begin by proving 1.2.a. The following standard reduction goes back at least to [14].
If P8M+10βR16M+2, then gd((2L+3β8Mβ11)ΞΎ8M+10β)β€8Mβ8, hence this bundle has (2L+3β16Mβ3) linearly independent sections, and thus there is an axial map
[TABLE]
The bundle here is the stable normal bundle, L is a sufficiently large integer, and gd refers to geometric dimension.
Let X, X1β, and X2β be elements of tmf8(β) described in [6] and also in Section 1. In Section 4, we will show that we may assume that fβ(X)=X1β+X2β, as was done in [6], since this is true
up to multiplication by a unit. Since
tmf2L+3β8Mβ8(P2L+3β8Mβ12)=0, we have
[TABLE]
Expanding, we obtain (M+12LβMβ1β)X1M+1βX22Lβ2Mβ2β+(M2LβMβ1β)X1MβX22Lβ2Mβ1β
as the only terms which are possibly nonzero.
Next we note that, with all uβs representing odd integers,
[TABLE]
where we have used Ξ±(M)=3 at the last step. Here and throughout, Ξ½(2eu)=e. Similarly, (M2LβMβ1β)=u3β(M2Mβ)=2Ξ±(M)u4β=23u4β.
Thus an immersion implies that in tmf2L+3β8Mβ8(P8M+10ΓP2L+3β16Mβ4), we have
[TABLE]
We recall [6, 2.6], which states that there is an equivalence of spectra Pb+8k+8ββ§tmfβΞ£8Pbkββ§tmf.
Combining this with duality, we obtain tmf8M+8(P8M+10)βtmfβ1β(Pβ3β)βZ/8, and so 8X1M+1βX22Lβ2Mβ2β=0. Here and throughout, Pnβ=Pnββ=RPβ/RPnβ1.
Similarly tmf2L+3β16Mβ8(P2L+3β16Mβ4)βtmf7β(P3β)βZ/16, and hence
16X1MβX22Lβ2Mβ1β=0. Duality also implies
[TABLE]
Calculations such as E2β(tmfββ(Pβ3ββ§P3β)), the E2β-term of the Adams spectral sequence (ASS), were made by Brunerβs minimal-resolution computer programs in our work on
[6]. This one is in a small enough range to actually do by hand. The result is given in Diagram
2.2.
Diagram 2.2**.**
E2β(tmfββ(Pβ3ββ§P3β)), ββ€15
[math]3$$7$$11$$15
The Z/8βZ/16 arising from filtration 0 in grading 14 in 2.2 is not hit by a differential
from the class in (15,0) because, as explained in the last paragraph of page 54 of [6], the class
in (15,0) corresponds to an easily-constructed nontrivial map. The monomials X1M+1βX22Lβ2Mβ2β and
X1MβX22Lβ2Mβ1β are detected in mod-2 cohomology, and so their duals emanate from filtration 0.
We saw in the previous paragraph that 8 and 16, respectively, annihilate these monomials, and hence also
their duals. Since the chart shows that the subgroup of tmf14β(Pβ3ββ§P3β) generated by classes of filtration
0 is Z/8βZ/16, we conclude that 8 and 16, respectively, are the precise orders of the monomials.
In particular, the order of X1MβX22Lβ2Mβ1β is 16, and hence the class in (2.1) is nonzero
since it has a term 8uX1MβX22Lβ2Mβ1β, and so (2.1) contradicts the hypothesized immersion.
Part b of 1.2 is proved similarly. If P8M+8 immerses in R16M+4, then there is an axial map
[TABLE]
and hence, up to odd multiples,
[TABLE]
since Ξ±(M)=2. We have tmf8M+8(P8M+8)βtmfβ1β(Pβ1β)βZ/2, and
[TABLE]
Thus the two monomials in (2) have order at most 2 and 8, respectively.
On the other hand, the group in (2) is isomorphic to tmf6β(Pβ1ββ§Pβ3β).
A minimal resolution calculation easier than the one in Diagram 2.2 shows that tmf6β(Pβ1ββ§Pβ3β)
has Z/2βZ/8 emanating from filtration 0 (and another Z/2βZ/8 in higher filtration). The monomials
of (2) are generated in filtration 0, and since the above upper bound for their orders equals the order
of the subgroup generated by filtration-0 classes, we conclude that the orders of the monomials in (2) are precisely 2 and 8, respectively,
and so the term 4X1MβX22Lβ2Mβ1β in (2) is nonzero, contradicting the immersion.
3. tmf-cohomology of PβΓPβ
In this section, we compute tmfβ(Pβ) and tmf8β(PβΓPβ) in positive gradings.
These will be used in the next section in studying the axial class in tmf-cohomology.
There is an element c4ββΟ8β(tmf) which reduces to v14ββΟ8β(bo); it has Adams filtration 4.
It acts on tmfβ(X) with degree β8. Recall also that Οββ(bo)=boββ is as depicted in 5.1.
We denote boβ=boβββ.
We use P1β and Pβ interchangeably.
Theorem 3.1**.**
There is an element Xβtmf8(P1β) of Adams filtration [math], described in [6], such that, in positive dimensions divisible by 8, tmfβ(P1β) is isomorphic as an algebra over Z(2)β[c4β] to Z(2)β[c4β][X].
In particular, each tmf8i(P1β) with i>0 is a free abelian group with basis
{c4jβXi+j:jβ₯0}. There is a class Lβt0(P1β) such that
β’
tmf0(P1β)* is a free abelian group with basis {L,c4jβXj:jβ₯1}, and*
β’
L2=2L* and LX=2X.*
Moreover, in positive dimensions tmfβ(P1β) is isomorphic as a graded abelian group to boβ[X],
and is depicted in Diagram 3.6.
Remark 3.2**.**
A complete description of tmfβ(P1β) as a graded abelian group could probably be obtained
using the analysis in the proof which follows, together with the computation of the E2β-term of the
ASS converging to tmfββ(Pβ1β), which was given in [10]. However, this is
quite complicated and unnecessary for this paper, and so will be omitted.
Proof.
We begin with the structure as graded abelian group. There are isomorphisms
[TABLE]
Since Hβ(tmf;Z2β)βA//A2β, there is a spectral sequence converging to tmfββ(X) with E2β(X)=ExtA2ββ(HβX,Z2β). Here A2β is the subalgebra of the mod 2 Steenrod algebra A generated
by Sq1, Sq2, and Sq4. Also Z2β=Z/2.
We compute E2β(Pβββ2β) from the exact sequence
Here we have initiated a notation that Pnmβ:=Hβ(Pnmβ).
A complete calculation of ExtA2ββ(Pβ1ββ,Z2β) was performed in [10], but all
we need here are the first few groups.
We can now form a chart for E2β(Pβββ2β) from (3.4), as in Diagram
3.5, where β indicate elements of ExtA2ββ(Pβ1ββ,Z2β) suitably positioned, and lines of negative
slope correspond to cases of qββξ =0 in (3.4).
Diagram 3.5**.**
tmfββ(Pβββ2β), β17β€ββ€2
-17$$-9$$-1$$\cdots
Dualizing, we obtain Diagram 3.6 for the desired tmfβ(P1ββ).
Diagram 3.6**.**
tmfβ(P1ββ), ββ₯β2
[math]8$$16$$\cdots
Naming of the generators Xi is clear since X has filtration 0. The free action
of c4β is also clear. The class L is (up to sign) the composite P1β@>Ξ»>>S0βtmf, where
Ξ» is the well-known Kahn-Priddy map. Thus L is the image of a class L^βΟ0(P1β).
Linβs theorem ([16]) says that Ο0(P1β)βZ2β§β, generated by L^.
Since Ο0(P1β)βko0(P1β) is an isomorphism, and, since (1βΞΎ)2=2(1βΞΎ) for a generator (1βΞΎ) of
ko0(P1β), we obtain L^2=2L^, and hence also for L. We chose the generator to be (1βΞΎ) rather than (ΞΎβ1) to avoid minus
signs later in the paper.
To prove the claim about LX, first note that, by the structure of tmf8(P1β), we must have
LX=p(c4βX)X for some polynomial p. Multiply both sides by L and apply the result about L2 to get
2LX=p(c4βX)LX, hence 2p=p2, from which we conclude p=2.
In tmfβ(P1βΓP1β), for i=1,2, let Liβ and Xiβ denote the classes L and X in the ith factor.
Note that there is an isomorphism as tmfββ-modules, but not as rings,
[TABLE]
Theorem 3.7**.**
In positive dimensions divisible by 8,
tmfβ(P1ββ§P1β) is isomorphic as a graded abelian group to a free abelian group on monomials X1iβX2jβ with i,j>0 direct sum with a free
Z[c4β]-module with basis {L1βX2iβ,X1iβL2β:iβ₯1}.
The product and Z[c4β]-module structure is determined from 3.1 and
[TABLE]
for certain integers Ξ³iβ with Ξ³0β divisible by 8.
The proof of this theorem involves a number of subsidiary results. They and it occupy the
remainder of this section.
We will use duality and exact sequences similar
to (3.4). But to get started, we need ExtA2ββ(PβP,Z2β). Here we have begun to abbreviate
P:=Pββββ. We begin with a simple lemma. Throughout this section, x1β and x2β denote
nonzero elements coming from the factors in H1(RPΓRP;Z2β).
Lemma 3.8**.**
(\cite[cite][\@@bibrefSeg])* There is a split short exact sequence of A-modules*
[TABLE]
Proof.
The Z2β is, of course, the subgroup generated by x0, which is an A-submodule.
A splitting morphism PβP@>g>>Z2ββP is defined by g(x1iββx2jβ)=x10ββx2i+jβ.
This is A-linear since
[TABLE]
The following result is more substantial. We will prove it at the end of this section.
Proposition 3.9**.**
There is a short exact sequence of A2β-modules
[TABLE]
where C has a filtration with
[TABLE]
and B has a filtration with
[TABLE]
The generator of Fpβ(C)/Fpβ1β(C) is x11βx28pβ1β; a basis over Z2β for C is
[TABLE]
A minimal set of generators as an A2β-module for the filtration quotients of B is {x18iβ1βx24jβ1β:i,jβZ}.
Corollary 3.10**.**
A chart for ExtA2βs,tβ(PβP,Z2β) in 8pβ3β€tβsβ€8p+4 is as suggested in Diagram 3.11, for all integers p. The big batch of towers in each grading β‘2(4) represents an infinite family of towers. The pattern of the other classes is repeated with vertical period 4. Thus, for example, in 8pβ1 there is
an infinite tower emanating from filtration 4i for each iβ₯0.
Diagram 3.11**.**
ExtA2βs,tβ(PβP,Z2β)* in 8pβ3β€tβsβ€8p+4*
We first note that ExtA2ββ(P,Z2β) is identical to the left portion
of Diagram 3.5 extended periodically in both directions. Also, ExtA2ββ(A2β/Sq1,Z2β)βExtA0ββ(Z2β,Z2β)
is just an infinite tower, and
[TABLE]
is given as in Diagram 3.14. We will show at the end of this proof that
[TABLE]
and similarly
[TABLE]
These would follow by induction on p once you get started,
but since p ranges over all integers, that is not automatic.
Thus ExtA2ββ(PβP,Z2β) is formed from
[TABLE]
using the sequences in 3.8 and 3.9. The Ext sequence of 3.8 must split,
and there are no possible boundary morphisms in the Ext sequence of 3.9, yielding the claim of the corollary.
To prove (3.12), let (s,t) be given, and choose p0β so that 8p0β<tβ23s+2. Since the highest degree element in A2β is in degree 23,
ExtA2βs,tβ(Fp0ββ(C),Z2β)=0. Actually a much sharper lower vanishing line
can be established, but this is good enough for our purposes. Thus, for this (s,t),
[TABLE]
for p1ββ€p0β, as both are 0.
Let p1β be minimal such that (3.13) does not hold. Then comparison of exact sequences implies that
[TABLE]
must be nonzero. But one or the other of these groups is always 0,111Actually this is not quite true; for one
family of elements we need to use h0β-naturality.
as both charts ExtA2ββ,ββ(Fp1ββ1β(C),Z2β)
and ExtA2ββ,ββ(Fp1ββ(C)/Fp1ββ1β(C),Z2β) are copies of Diagram 3.14 displaced by 4 vertical
units from one another. Thus (3.13) is true for all p1β, and hence (3.12) holds.
A similar proof works when C is replaced by B.
Diagram 3.14**.**
ExtA2ββ(A2β/Sq2,Z2β)**
[math]β―
Now we can prove a result which will, after dualizing, yield Theorem 3.7. The groups ExtA1ββ(Z2β,Z2β)
to which it alludes are depicted in 5.1. The content of this result is pictured in Diagram
3.18.
Proposition 3.15**.**
In dimensions tβsβ‘2mod4 with tβsβ€β10, ExtA2ββ(Pβββ2ββPβββ2β,Z2β) consists of i infinite towers emanating from filtration [math] in dimensions β8iβ6 and β8iβ10,
together with the relevant portion of two copies of ExtA1ββ(Z2β,Z2β) beginning in filtration 1 in each dimension β8iβ2.
The generators of the towers in β8iβ10 correspond to cohomology classes x1β9βx2β8iβ1β,β¦,x1β8iβ1βx2β9β.
The generators of the two copies of ExtA1ββ(Z2β,Z2β) in β8iβ2 arise from h0β times classes corresponding
to x1β1βx28iβ1β and x1β8iβ1βx2β1β.
Proof.
Using exact sequences like (3.4) on each factor, we build ExtA2ββ,ββ(Pβββ2ββPβββ2β,Z2β) from A:=ExtA2ββ,ββ(PβP,Z2β), B:=ExtA2βββ1,ββ(Pβ1βββP,Z2β), C:=ExtA2βββ1,ββ(PβPβ1ββ,Z2β),
and D:=ExtA2βββ2,ββ(Pβ1βββPβ1ββ,Z2β), with possible d1β-differential
from A and into D. In the range of concern, tβsβ€β9, the D-part will not be present, and the
part of Diagram 3.11 in dimension ξ β‘2 mod 4 will not be involved in d1β. Using [17] for B and C,
the relevant part, namely the portion of A in dimension β‘2 mod 4, together with B and C, is pictured
in Diagram 3.16.
Diagram 3.16**.**
Portion of A+B+C
-2$$2$$6$$8p+
In dimension 8pβ2, the towers in A arise from all cohomology classes x1β8iβ1βx2β8jβ1β with i+j=βp,
while in dimension 8p+2, they arise from x18iβ1βx28j+3ββΌx18i+3βx28jβ1β. The finite towers in B arise from
x14iβ1βx28jβ1β with iβ₯0, and those from C from x18iβ1βx24jβ1β with jβ₯0. The homomorphism
[TABLE]
which is equivalent to the d1β-differential mentioned above, sends classes to those with the same name.
In dimension β€β10, this is surjective, with kernel spanned by classes with both components <β1. In dimension
β8iβ6 and β8iβ10, there will be i such classes. We illustrate by listing the classes in the first few gradings:
[TABLE]
These kernel classes yield infinite towers emanating from filtration 0.
For each p<0, the towers arising from x14jβ1βx28pβ1β, jβ₯0, in A combine with those in the p-summand of
[TABLE]
as in Diagram 3.17 to yield one of the copies of ExtA1ββ(Z2β,Z2β) arising from filtration 1.
An identical picture results when the factors are reversed.
Diagram 3.17**.**
Part of ExtA2ββ(Pβββ2ββPβββ2β,Z2β)
βΉ
Putting things together, we obtain that in dimensions less than β8,
ExtA2ββ(Pβββ2ββPβββ2β,Z2β) consists of
a chart described in Proposition 3.15 and partially illustrated in
Diagram 3.18 together with the classes in Diagram 3.11
which are not part of the infinite sums of towers in dimension β‘2 mod 4.
The only possible differentials in the Adams spectral sequence of
Pβββ2ββ§Pβββ2ββ§tmf involving the classes in
dimensions 8pβ2 with p<0 are from the towers in 8pβ1 in
Diagram 3.11, but these differentials are shown to be 0 as in [6, p.54].
Similarly to (3.3), we have
[TABLE]
and so we obtain a turned-around version of Diagram 3.18, of the same general sort
as Diagram 3.6, as a depiction
of a relevant portion of tmfβ(P1ββ§P1β), with the labeled columns in Diagram 3.18
corresponding to cohomology gradings 24, 16, and 8.
The classes X1iβX2jβ described in Theorem 3.7 are detected
by the S-duals of the classes from which the filtration-0 towers in
dimensions 8pβ2 in Diagram 3.18 arise, and so they can be chosen to be the
corresponding elements of tmf8β(P1ββ§P1β). Similarly the classes
L1βX2iβ and X1iβL2β have Adams filtration 1, and so one would
anticipate that they represent the duals of the generators of the two towers in dimension
8pβ2 with p<0 in Diagram 3.18. This seems a bit harder to
prove using the Adams spectral sequence; however, the Atiyah-Hirzebruch
spectral sequence shows this quite clearly. The class X1iβ is detected by
H8i(P1β;Ο0β(tmf)), while L is detected by H1(P1β;Ο1β(tmf)).
Under the pairing, their product is detected in H8i+1(P1β;Ο1β(tmf)),
clearly of Adams filtration 1.
The last part of Theorem 3.7 deals with the action of c4β on the
monomials X1iβX2jβ. Since tmf is a commutative ring spectrum, tmfβ(P1ββ§P1β)
is a graded commutative algebra over tmfββ. The action c4β(X1βX2β) must be of
the form βiβ₯0βΞ³iβc4iβ(L1βX2iβ+X1iβL2β) as these are the only elements
in tmf8(P1ββ§P1β), and the class must be invariant under reversing factors.
The divisibility of Ξ³0β by 8 follows since c4β has Adams filtration 4.
Having just completed the proof of Theorem 3.7, we conclude this section with
the postponed proof of Proposition 3.9.
Let C denote the A2β-submodule of (P/Z2β)βP
generated by all x11βx28pβ1β, pβZ.
Note that Sq2(x11βx28pβ1β)=Sq4Sq6(x11βx28pβ9β).
Thus a basis of A2β/Sq2 acting on all x11βx28pβ1β spans C.
The 24 elements in a basis of A/Sq2 acting on x11βx27β yield x11βx27β, x11βx28β+x12βx27β, x12βx29β+x14βx27β,
x11βx211β+x12βx210β, x11βx212β+x12βx211β, x11βx213β+x12βx212β, x11βx214β+x12βx213β, x12βx213β+x14βx211β, x14βx211β+x18βx27β,
x12βx214β+x14βx212β, x11βx216β+x14βx213β, x11βx217β+x12βx216β, x12βx216β+x14βx214β, x11βx218β+x12βx217β, x12βx217β+x18βx211β,
x12βx218β+x18βx212β, x11βx220β+x14βx217β, x14βx217β+x18βx213β, x12βx220β+x14βx218β, x14βx218β+x18βx214β, x14βx220β+x18βx216β,
x11βx224β+x18βx217β, x12βx224β+x18βx218β, and x14βx224β+x18βx220β. These classes with second components shifted
by all multiples of 8 exactly comprise the basis for C described in the proposition.
The procedure to establish the structure of B=((P/Z2β)βP)/C is similar but more
elaborate. For the 32 elements ΞΈ in a basis of A2β/Sq1, we list ΞΈ(x1β1βx2β1β)
and ΞΈ(x1β1βx23β). Then we show that these, with each component allowed to vary by multiples
of 8, together with C, fill out all of (P/Z2β)βP.
It is convenient to let Q denote the quotient of (P/Z2β)βP by C and all elements ΞΈ(x18iβ1βx28jβ1β)
and ΞΈ(x18iβ1βx28j+3β). We will show Q=0. This will complete the proof of Proposition 3.9, implying in particular that
Sq1(x18iβ1βx28jβ1β) and Sq1(x18iβ1βx28j+3β) are decomposable over A2β.
A separate calculation is performed
for each mod 8 value of the degree. Here we use repeatedly that the A2β-action on xi depends
only on i mod 8.
We illustrate with the case in which degree β‘0 mod 8. The other 7 congruences are handled
similarly, although some are a bit more complicated.
A basis of A2β/Sq1 in degree β‘2 mod 8 acting on x1β1βx2β1β yields the following elements:
x1β1βx21β+x10βx20β+x11βx2β1β, x12βx26β+x16βx22β, x1β1βx29β+x13βx25β+x14βx24β+x15βx23β+x19βx2β1β, and x14βx212β+x112βx24β.
A basis of A2β/Sq1 in degree β‘6 mod 8 acting on x1β1βx23β yields the following elements:
x12βx26β+x13βx25β+x14βx24β+x15βx23β, x1β1βx29β+x12βx26β+x15βx23β, x14βx212β+x16βx210β+x110βx26β+x112βx24β, and x18βx216β+x116βx28β.
Because we allow both components to vary by multiples of 8, we will list just the first component of the ordered
pairs. These are considered as relations in Q.
Thus the relation R1β below really means that all x18iβ1βx28j+1β+x18iβx28jβ+x18i+1βx28jβ1β become 0 in Q.
[TABLE]
We will use these relations to show that all classes (in degree β‘0 mod 8) are 0 in Q.
First, R8β implies that all classes X8iβ are congruent to one another. Since X0β is 0 in the
quotient due to P/Z2β, we conclude that all classes X8iβ are 0 in Q. Next, R4β implies
that all X8i+4β are congruent to one another. Since X4β+X8ββC, and we have just shown that X8ββ‘0
in Q, we deduce that all X8i+4β are 0 in Q. Now we use R2β+R7β to see that all X8i+2β+X8i+4β
are congruent to one another, then that X2β+X4ββC to deduce all X8i+2β+X8i+4ββ‘0, and finally
the result of the previous sentence to conclude all X8i+2ββ‘0. Then R2β implies all X8i+6ββ‘0.
Now R1β+R3β+R5β, together with relations previously obtained, implies all X8i+1β are congruent to one another,
and since X1ββC, we conclude all X8i+1ββ‘0. Finally R1β implies X8iβ1ββ‘0, R6β implies
X8i+5ββ‘0, and then R3β implies X8i+3ββ‘0.
4. Careful treatment of axial class
In this section, we fill the gap in the proof in [6] of its Theorem 1.1
by careful consideration of the possible βother termsβ in the axial class
discussed in the Introduction. We show that, at least as far as the monomials cX1iβX2jβ in its powers are concerned, the axial class equals
u(X1β+X2β), where u is a unit in tmf0(RPβΓRPβ).
Thus the βth power of the axial class is nonzero in tmf8β(RPnΓRPm)
if and only if (X1β+X2β)β is nonzero there, and the latter is the condition
which yielded the nonimmersions of [6, 1.1]. Thus we have a complete proof of [6, 1.1].
If PnΓPm@>f>>Pm+k is an axial map, then
there is a commutative diagram
[TABLE]
where g is the standard multiplication of Pβ, since Pβ=K(Z2β,1).
Since Xβtmf8(Pm+k) has been chosen to extend over Pβ, we obtain that
fβ(X) is the restriction of gβ(X). By Theorem 3.7 and the symmetry of g,
we must have
[TABLE]
for some integers ΞΊiβ. This is what we call the βaxial class.β
Then gβ(Xβ) equals the βth power of (4.1). Using the formulas
for Li2β, LiβXiβ, and c4β(X1βX2β) in 3.1 and 3.7 and the binomial theorem,
this βth power can be written in terms of the basis described in 3.7.
If some ΞΊiββs are nonzero, the coefficients of X1iβX2ββiβ in gβ(Xβ) will not equal
(iββ), as was claimed in [6].
We will study this possible deviation carefully.
One simplification is to treat L1β and L2β as being just 2.
Note that Liβ acts like 2 when multiplying by Xiβ, and if, for example, L1β is present
without X1β, then the terms c4iβL1βX2jβ cannot cancel our
X1kβX2ββ-classes because both are separate parts of the basis. You have
to carry the terms along, because they might get multiplied by an X1β,
and then it is as if L1β=2. We will incorporate this important simplification throughout
the remainder of this section.
For example, one easily checks that, using L12β=2L1β and L1βX1β=2X1β, we obtain
[TABLE]
The exponent of 2 in each monomial of (X1β+3X2β)4β80X24β is the same as that in (X1β+X2β)4,
and L1βX24β is a separate basis element.
With this simplification, the axial class in (4.1) becomes
[TABLE]
for some
integers ΞΊiβ. There was another term 2ΞΊ0β(X1β+X2β), but
it can be incorporated into the leading (X1β+X2β). The odd multiple that it can create is not
important.
for some
integers Ξ³kβ. The 16 comes from Ξ³0β=8 and Liβ=2. Actually we donβt really know that
Ξ³0β=8, even just up to multiplication by a unit, but it is divisible by 8 and the possibility
of equality must
be allowed for. This gives
[TABLE]
Here we use that in a graded tmfββ-algebra tmfβ(X) with even-degree elements,
c(xy)=cxβ y, for cβtmfββ and x,yβtmfβ(X).
There is an iterative nature to the action of c4β in (4.4), but the leading coefficient 16
enables us to keep track of 2-exponents of leading terms in the iteration. (As observed above, the leading
coefficient might be an even multiple of 16, which would make the terms even more highly 2-divisible. We assume the worst, that it equals 16.) We obtain the following
key result about the action of c4β on monomials in X1β and X2β.
Theorem 4.5**.**
There are 2-adic integers Aiβ such that
[TABLE]
Remark 4.6**.**
This formula will be evaluated on (i.e. multiplied by) monomials X1kβX2ββ. One might worry that
the negative powers of X1β or X2β in 4.5 will cause nonsensical negative powers in c4βX1kβX2ββ.
This will, in fact, not occur because the monomials on which we act always have total degree greater than the
dimension of either factor. Thus if, after multiplication by c4β, a term with negative exponent of Xiβ appears,
then the accompanying X3βijβ-term will be 0 for dimensional reasons.
The defining equation (4.3) may be written as, with ΞΈ=c4βX1βX2ββ and z=X1β/X2ββ,
[TABLE]
Let piβ=zi+zβi. We will show that
[TABLE]
for certain 2-adic integers Aiβ, which interprets back to the claim
of 4.5.
Note that piβpjβ=pi+jβ+pβ£iβjβ£β, and hence
[TABLE]
where L is a sum of integer multiples of pjβ with j<βieiβ and jβ‘βieiβ mod 2.
We will ignore for awhile the coefficients Ξ³iβ which occur in (4.7). This is allowable if we agree that
when collecting terms, we only make crude estimates about their 2-divisibility. We have
[TABLE]
Note that the only terms that actually get evaluated must end with a 16p1β factor.
Now let T1β=16p1β and, for iβ₯2, let Tiβ=2ΞΈiβ1piβ. Each term in the expansion of ΞΈ
involves a sequence of choices. First choose Tiβ for some iβ₯1, and then if i>1 choose (iβ1) factors
Tjβ, one from each factor of ΞΈiβ1. For each of these Tjβ with j>1, choose jβ1 additional factors,
and continue this procedure.
This builds a tree, and we donβt get an explicit product term until every branch ends with T1β. Each selected
factor Tjβ with j>1 contributes a factor 2pjβ. There will also be binomial coefficients and the omitted
Ξ³iββs occurring as additional factors.
For example, Diagram 4.9 illustrates the choices leading to one term in the expansion of ΞΈ.
This yields the term 2p2ββ 2p4ββ 16p1ββ 2p2ββ 16p1ββ 2p3ββ 16p1ββ 2p2ββ 16p1β,
which equals 221(p17β+L), where L is a sum of piβ with i<17 and i odd. By induction, one sees
in general that the sum of the subscripts emanating from any node, including the subscript of the node itself, is odd.
The important terms are those in which T2β is chosen k times (kβ₯0) and then T1β is chosen. These give
(2p2β)kp1β with no binomial coefficient. This term is 2k+4(p2k+1β+L). Note that a term 2k+4p2i+1β
with i<k obtained from L will be more 2-divisible than the 2i+4p2i+1β term that was previously obtained.
Thus it may be incorporated into the coefficient of that term.
All other terms will be more highly 2-divisible than these. For example, the first would arise from choosing
T3β then two copies of T1β. This would give 2p3ββ 24p1ββ 24p1β=29p5β+L, and the 29p5β can
be combined with the 26p5β obtained from choosing T2β then T2β then T1β. Incorporating Ξ³iββs may make
terms even more divisible, but the claim of (4.8) is only that p2i+1β occurs with coefficient divisible by 24+i.
Now we incorporate 4.5 into (4.2) to obtain the following key result, which we prove at the
end of the section.
Theorem 4.10**.**
The monomials ciβX1iβX2nβiβ in the nth power of the axial class in
tmf8n(RPβΓRPβ) are equal to those in the nth power of
[TABLE]
where u is an odd 2-adic integer and Ξ±iβ are 2-adic integers.
The factor which accompanies (X1β+X2β) in (4.11) is a unit in tmfβ(RPβΓRPβ); we referred to it earlier as u.
Indeed, its inverse is a series of the same form, obtained by solving a sequence of equations. This justifies the claim in the first paragraph of this
section regarding retrieval of the nonimmersions of [6, 1.1].
We must also observe that restriction to tmf8β(RPnΓRPm) of the non-X1iβX2ββiβ parts of the basis of tmf8β(RPβΓRPβ) cannot cancel the X1iβX2ββiβ terms essential for the
nonimmersion. This is proved by noting that these elements such as L1βX2ββ and c4iβL1βX2β+iβ
will restrict to a class of the same name in tmf8β(RPnΓRPm), and will be 0 there for dimensional
reasons, since 8β>n.
Let gβ(X) denote the axial class as in (4.1). From (4.2) and 4.5, the difference
gβ(X)β(X1β+X2β) equals
[TABLE]
We let z=X1β/X2ββ and pjβ=zj+zβj as in the proof of 4.5.
The summand with i=2t becomes
[TABLE]
Here k is a sum of j-values taken from the various
factors in the ith power. Also, in pjβ+L, L denotes a combination of ptββs with t<j.
Noting (p2tβ+L)(p2k+iβ+L)=p2k+2iβ+L, this becomes
[TABLE]
The argument when i=2t+1 is similar but slightly more complicated because (X1i+1β+X2i+1β) is not divisible by (X1β+X2β). We obtain
[TABLE]
For one of the factors of the ith power, say the first, we treat p2j+1β as X1βX2ββX1β+X2ββ(p2jβ+L). The expression then becomes
[TABLE]
where k is obtained as in the previous case. We again obtain (4.12).
Thus when gβ(X)β(X1β+X2β) is written as (X1β+X2β)βΞ²jβp2jβ, the coefficient Ξ²jβ satisfies
Ξ½(Ξ²jβ)β₯(jβ1)+4+1. Here the (jβ1)+4 comes from the case i=1, k=jβ1 in (4.12), and the extra +1 is the
factor 2 which has been present all along. This yields the claim of (4.11).
We begin by reviewing Asteyβs argument. There is a commutative diagram, in which RP=RPβ and CP=CPβ
[TABLE]
The generator XRββBP2(RP) satisfies XRβ=hβ(X). We also have that mCββ(1Γ(β1))βdCβ is
null-homotopic.
The key fact, which will fail for tmf, is BPβ(CPΓCP)βBPβ[X1β,X2β].
The axial class is mRββ(XRβ). It equals (hΓh)β(1Γ(β1))βmCββ(X). But
[TABLE]
By the above βkey fact,β dCββ is the projection BPβ[X1β,X2β]βBPβ[X] in which
each Xiββ¦X. The kernel of this projection is the ideal (X2ββX1β). To see this,
just note that in grading 2n a kernel element must be βciβX1iβX2nβiβ
with βciβ=0, and hence is
[TABLE]
Thus (1Γ(β1))βmCββ(X)=(X2ββX1β)u for some uβBPβ(CPΓCP). This u is a unit
by consideration of its reduction to Hβ(β;Z), as in [2]. Since hβ(u) will then be
a unit in BPβ(RPΓRP) and hβ(Xiβ)=XRβiβ, we obtain the claim about the axial class
being a unit times XRβ2ββXRβ1β.
In order to see if there is any chance of adapting this to tmf, we compute tmfβ(CPβ) and
tmfβ(CPβΓCPβ) in positive gradings.
We begin with the relevant Ext calculations.
Let bo=ExtA1ββ,ββ(Z2β,Z2β). Recall that a chart for this is given as in Diagram 5.1, extended
with period (tβs,s)=(8,4).
Thus the chart for ExtA2ββ,ββ(M10β,Z2β) consists of a copy of bo shifted by
(tβs,s)=(6i,i) units for each iβ₯0.
Proof.
There is a short exact sequence of A2β-modules
[TABLE]
This yields a spectral sequence which builds ExtA2ββ,ββ(M10β,Z2β)
from
[TABLE]
Since ExtA2ββ,ββ(A2β//A1β,Z2β)βbo, one easily checks that there are
no possible differentials in this spectral sequence.
Let Cnmβ=Hβ(CPnmβ;Z2β).
Theorem 5.3**.**
There is an additive isomorphism
[TABLE]
Of course Ξ£ applied to a module or an Ext group just means to increase the t-grading by 1.
Proof.
There is a filtration of Cββββ with Fpβ/Fpβ1ββΞ£8pβ2M10β
for pβZ. We have Sq2ΞΉ8pβ2β=Sq4Sq2Sq4ΞΉ8pβ10β. The same argument used in the
last paragraph of the proof of Corollary 3.10 works to initiate an inductive
proof of the Ext-isomorphism claimed in the theorem.
Corollary 5.4**.**
In gradings (tβs) less than β1,
[TABLE]
Proof.
There is an exact sequence
[TABLE]
The result is immediate from this and 5.3, since qββ sends the initial tower in F0β/Fβ1β isomorphically
to the initial tower in ExtA2ββ(Cβ1ββ,Z2β).
The A-modules C1ββ and Ξ£2Cβββ2β are dual. Thus, by [9, Prop 4],
[TABLE]
There is a ring structure on ExtA2ββ,ββ(Z2β,C1ββ). We deduce the following result,
which is pictured in Diagram 5.12.
Corollary 5.5**.**
In (tβs) gradings β€0, there is a ring isomorphism
[TABLE]
where XβExt0,β8.
Proof.
We apply the duality isomorphism to 5.4. The multiplicative structure is obtained
from the observation that the powers of the class in Ext0,β8 equal the class in Ext0,β8i
for each i>0.
The Ext groups computed here are the E2β-term of the ASS converging to tmfββ(CPβ).
We will consider the differentials in this spectral sequence after performing the Ext calculation
relevant for tmfβ(CPβΓCPβ).
Now we consider Cβββ2ββCβββ2β.
Now x1β and x2β denote elements of H2(CP;Z2β). Let E2β denote the exterior subalgebra generated
by the Milnor primitives of grading 1, 3, and 7. Note that A2β//E2β has a basis with elements of
grading 0, 2, 4, 6, 6, 8, 10, and 12. Finally we note that for any jβ‘β2 mod 8 with jβ€β10, there is a nontrivial A2β-morphism Cβββ2β@>Ο>>Ξ£jZ2β.
Lemma 5.6**.**
Let
[TABLE]
Let S denote the set of all classes x18iβ2βx28jβ2β with iβ€β1 and jβ€β2, together with the classes
x18iβ2βx28j+2β with iβ€β1 and jβ€β1. Then
K is the direct sum of a free A2β//E2β-module on S with a single relation Sq4Sq2Sq4(x1β10βx2β6β)=0.
Proof.
Since the generators of E2β have odd grading, A2β//E2β acts on any element of these
evenly-graded modules. The action of A2β//E2β on x1β2βx2β2β yields the additional elements x1β2βx20β+x10βx2β2β,
x1β2βx22β+x10βx20β+x12βx2β2β, x1β2βx24β+x14βx2β2β, x10βx22β+x12βx20β, x10βx24β+x14βx20β,
x1β2βx28β+x12βx24β+x14βx22β+x18βx2β2β, and x10βx28β+x18βx20β.
The action of A2β//E2β on x1β2βx22β yields the additional elements x10βx22β+x1β2βx24β, x10βx24β+x12βx22β, x12βx24β+x14βx22β,
x12βx24β+x1β2βx28β, x10βx28β+x14βx24β, x12βx28β+x18βx22β, and x14βx28β+x18βx24β.
Each exponent can be decreased by any multiple of 8.
One can easily check that in each grading all classes in Cβββ2ββCβββ2β
are obtained exactly once from the described elements in K together with Cβββ2ββΞ£β10Z2β.
There are four cases, for the four even mod 8 values. We illustrate with the case of grading 4 mod 8.
We will just consider the specific value β28, but it will be clear that it generalizes to all gradings
β‘4 mod 8. Letting Xiβ denote x1iβx2β28βiβ, we have:
(1)
From generators in β28, we obtain just Xβ10β in K. The class Xβ18β is in Cβββ2ββΞ£β10Z2β.
2. (2)
From generators in β32, we obtain Xβ8β+Xβ6β, Xβ16β+Xβ14β, and Xβ24β+Xβ22β.
3. (3)
From generators in β36, we obtain Xβ8β+Xβ4β and Xβ16β+Xβ12β.
4. (4)
From generators in β40, we obtain Xβ4β, Xβ12β+Xβ8β, Xβ20β+Xβ16β, and Xβ24β.
Note in (4) that X0β and Xβ28β do not appear because each component must be β€β4 and the components
sum to β28.
One easily checks that the 11 classes listed above, including Xβ18β, form a basis for the
space spanned by Xβ4β,β¦,Xβ24β, in an orderly fashion that clearly generalizes to
any grading β‘4 mod 8. A similar argument works in the other three congruences.
There are some minor variations in the top few dimensions.
Now we dualize. There is a pairing
[TABLE]
Let Xiβ denote the class in grading β8 coming from the ith factor.
Then we obtain
The structure as graded abelian group is straightforward from Lemma 5.6, Corollary 5.5, and the duality isomorphism
[TABLE]
We use that ExtA2ββ(A2β//E2β,Z2β)βZ2β[v0β,v1β,v2β]. The reason that we only assert the
structure in dimension β€β8 is due to the Ξ£β10 in the cokernel part of Lemma 5.6, and
that Theorem 5.5 was only valid in dimension β€0. In the range under consideration,
the relation on the top class in Lemma 5.6 does not affect Ext.
The ring structure in filtration 0 comes from HomA2ββ(Z2β,C1βββC1ββ)
being isomorphic to elements of C1βββC1ββ annihilated by Sq2 and Sq4,
which has as basis all elements x14iββx24jβ and (x14iββx24jβ)(x14ββx22β+x12β+x24β).
Now we show that ExtA2β1,β8n+2β(Z2β,C1βββC1ββ)=Z2β, and h1β times each monomial in ExtA2β0,β8nβ(Z2β,C1βββC1ββ) equals the nonzero element here. An element in ExtA2β1,β8n+2β(Z2β,C1βββC1ββ)=Z2β is an equivalence class of morphisms
[TABLE]
which increase grading by 8nβ2, and yield a trivial composite when preceded by
[TABLE]
Morphisms h which can be factored as
[TABLE]
are equivalent to 0 in Ext.
We illustrate with the case n=3. There are A2β-morphisms increasing grading by 22 sending either Ξ£2A2β or Ξ£4A2β to any one of the following classes:
[TABLE]
The classes are listed in this order because any two adjacent monomials are equivalent using as
k in (5.8) the morphism sending the generator to the indicated classes in succession:
[TABLE]
For example, (Sq2,Sq4)(x11βx210β)=(x12βx210β,x11βx212β). Thus all classes in (5.9)
are equivalent to one another.
That h1β times any monomial X1iβX2nβiβ equals this nonzero element of ExtA2β1,8n+2β(Z2β,C1βββC1ββ) follows from usual Yoneda product consideration.
If 0βZ2ββC0ββC1ββ is the beginning of a minimal A2β-resolution, with C1β=Ξ£1A2ββΞ£2A2ββΞ£4A2β, then h1βX1iβX2nβiβ is represented by the composite
C1ββC0ββC1βββC1ββ sending ΞΉ2ββ¦ΞΉβ¦X1iβX2nβiβ, and this is
equivalent to the element described in the previous paragraph.
Here is a schematic way of picturing Theorem 5.7. We first list the generators in grading greater than β32.
Then for each of the two types of generators, we list the structure arising from them in the first 10 dimensions.
The bo[v2β]-structure in the left half of Diagram 5.11 arises from one tower in dimensions β24 and β16, while the Z2β[v0β,v1β,v2β]-structure in the right half of diagram 5.11 arises from the other towers in
Diagram 5.10.
Diagram 5.10**.**
Generators of ExtA2ββ(Z2β,C1βββC1ββ)
-28$$-24$$-20$$-16$$-12
Diagram 5.11**.**
Structure on two types of generators
[math][math]10$$10
Now we consider the differentials in the ASS converging to tmfβ(CPβ) and then
for tmfβ(CPββ§CPβ). The gradings are negated when considered as tmf-cohomology
groups. Corollary 5.5
gives the E2β-term converging to [Ξ£βCP1ββ,tmf]βtmfββ(CP1ββ).
We will maintain the homotopy gradings until just before the end.
In diagram 5.12, we depict a portion of the E2β-term of this ASS in gradings β16 to 1.
There are also classes in higher filtration arising from powers of v14β and v2β acting on
generators in lower grading. The elements indicated by ββs are involved in differentials,
as explained later.
Diagram 5.12**.**
A portion of E2β for [Ξ£βCPβ,tmf]
-16$$-8[math]
We will prove the following key result about differentials in this ASS.
Theorem 5.13**.**
The nonzero differentials in the ASS converging to
[Ξ£βCPβ,tmf], β<1, are given by
[TABLE]
for Ο΅=0,1, i,jβ₯0, kβ₯1.
Here h1β, v14β, and v2β have the usual Exts,t gradings (s,t)=(1,2), (4,12), and
(1,7), respectively.
Diagram 5.12 pictures the situation for k=1 and small values of i and j.
The elements indicated by ββs are involved in the differentials. The resulting
picture is nicer if the filtrations of all classes built on Xβ2k+1 are increased by 1.
There is a nontrivial extension (multiplication by 2) in dimension β6 due to the preceding
differential.
This is equivalent to the way that buββ is formed from boββ and Ξ£2boββ. We obtain
Diagram 5.14 from Diagram 5.12 after the differentials, extensions, and filtration shift
are taken into account.
Diagram 5.14**.**
Diagram 5.12 after differentials and filtration shift
-16$$-8[math]
The regular sequence of towers in the chart beginning in filtration 1 in dimension β10 is interpreted
as v1iβv2β, iβ₯0.
After negating dimensions to switch to cohomology indexing, we obtain the following result, which is immediate from 5.13 after the extensions such as just seen are taken into account.
Theorem 5.15**.**
In positive gradings, there is an isomorphism of graded abelian groups
[TABLE]
Here Z16ββtmf16(CP1ββ), and β£v1ββ£=β2 and β£v2ββ£=β6.
Recall that boβ=boβββ with boββ as suggested in 5.1. Much of the ring structure of tmfβ(CP1ββ) is described in 5.15, since
boββ and v2βZ(2)β[v1β,v2β] are rings, and it is quite clear how to multiply an element in boββ by one in
v2βZ(2)β[v1β,v2β]. Because of the filtration shift that led to the identification of some of the
classes in v2βZ(2)β[v1β,v2β], we hesitate to make any complete claims about the ring structure.
A complete computation of tmfβ(CPβ) was made in [5]. See there especially Theorem 7.1 and
Diagram 7.1. At first glance, the two descriptions appear quite different, but they seem to be compatible.
We first prove that there is a nontrivial class in [Ξ£β16CP,tmf] detected in filtration 0.
This is obtained using the virtual bundle 8(Hβ1)β(H3βH), where H denotes the complex Hopf bundle.
Considered as a real bundle ΞΈ, this bundle satisfies w2β(ΞΈ) and p1β(ΞΈ)=0. Here we use
from [18] that p1β generates the infinite cyclic summand in H4(BSO;Z) and satisfies rβ(p1β)=c12ββ2c2β
under BU@>r>>BSO, and Οβ(p1β)=2e1β under BSpin@>Ο>>BSO, where H4(BSpin;Z) is an infinite
cyclic group generated by e1β. The total Chern class of 9HβH3 is
[TABLE]
and hence
[TABLE]
Thus e1β(ΞΈ)=0,
hence CPβ@>ΞΈ>>BSpinβK(Z,4) is trivial, and so ΞΈ lifts to a map CPββBO[8].
Hence its Thom spectrum induces a degree-1 map T(ΞΈ)βMO[8]. Since Ο3(H)=H3βH, by [19]
ΞΈ is J(2)β-equivalent to 8(Hβ1), and hence its Thom spectrum is T(8(Hβ1))=Ξ£β16CP8ββ.
Using the Ando-Hopkins-Rezk orientation ([1]) MO[8]βtmf, we obtain our desired class as the composite
[TABLE]
We will deduce our differentials from the d3β-differential E34,21ββE37,23β
in the ASS converging to Οββ(tmf). This can be seen in [13, p.537] or [11, Thm 2.2]. See
Remark 5.17 for additional explanation.
It is not difficult to show that, with M10β as in 5.2, the morphism
[TABLE]
induced by the nontrivial A2β-map M10ββZ2β sends the Z2β in ExtA2β7,23β(Z2β,Z2β) which is not
part of the infinite tower to h12βv14βv2β.
We prefer to think about the ASS for tmfββ(Ξ£2CPβββ2β), which, as we have noted, is isomorphic
to that of [Ξ£βCP1ββ,tmf]. The E2β-term was described in 5.4. Let Sβ16βΞ£2CPβββ2ββ§tmf
correspond to the map in (5.16). Since E2β(CPβββ2ββ§tmf) in negative dimensions is built from
copies of ExtA2ββ(M10β,Z2β), we deduce from the previous paragraph that h12βv14βv2βgβ16β
in the ASS for tmfββ(Ξ£2CPβββ2β) must be hit by a d2β- or d3β-differential, since it is the
image of a class hit by a d3β. The only possibility is that it be d2β from h1βv14βgβ8β, as indicated
by the dotted line
in Diagram 5.12. Naturality of differentials with respect to h1β and v14β implies the differentials
of 5.13 for Ο΅=0,1, all i, j=0, and k=1. Using the diagonal map of CP1ββ and the
multiplication of tmf, powers of (5.16) give similar nontrivial elements in [Ξ£β16kCP1ββ,tmf]
for all kβ₯1,
and by the argument just presented, we establish the differentials of 5.13 for all k (with j=0 still).
The only possible differentials on v2βgβ16β would be some drβ with r>2 hitting an element which is
acted on nontrivially by h1β. However h1βv2βgβ16β has become 0 in E3β since it was hit by a d2β-differential.
Thus a nonzero differential on v2βgβ16β would contradict naturality of differentials with respect to
h1β-action. Hence there is a map Sβ10βΞ£2CPβββ2ββ§tmf hitting v2βgβ16β, and the argument of
the previous paragraph implies that d2β(h1βv14βv2βgβ8β)=h12βv14βv22βgβ16β and then other related
differentials. This now establishes the differentials of 5.13 when j=1, and sets in motion an
inductive argument to establish these differentials for all jβ₯1.
No further differentials in the spectral sequence are possible, by dimensional and h1β-naturality considerations.
Remark 5.17**.**
The proof of the key d3β-differential in the ASS of tmf from the 17-stem to the 16-stem, which was cited above,
has not had a thorough proof in the literature. Giambalvoβs original argument was incorrect and his correction
merely refers to βa homotopy argument.β The current authors cited Giambalvoβs result in [11] without
additional argument. We provide some more detail here regarding this differential.
The relevant portion of the ASS of tmf appears in Diagram 5.18. In [13] and [11],
this was pictured as the ASS of MO[8], but through dimension 18,
The differentials in the ASS converging to tmfββ(CPβββ2ββ§CPβββ2β)
are implied by the same considerations that worked for CPβββ2β.
The Z2β[v0β,v1β,v2β]-parts in Theorem 5.7 cannot support differentials
by dimensionality and h1β-naturality. For the bo-like part, we prefer thinking about
it as [Ξ£β+4CP1βββ§CP1ββ,tmf]βtmfβββ4(CP1βββ§CP1ββ), where the product structure is more
apparent.
Let Znβ denote the nonzero element of ExtA2β0,β8nβ(Z2β,C1βββC1ββ)/ker(h1β).
By Theorem 5.7, Znβ can be represented by X1iβX2nβiβ for any 1β€i<n. If n is even and nβ₯4, choosing i even, Znβ is an infinite cycle because it is an external product
of infinite cycles. Hence by the proof of Theorem 5.13,
[TABLE]
for Ο΅=0,1, i,jβ₯0, and kβ₯2.
Finally, X1βX2β is an infinite cycle since there is nothing that it can hit. Also,
h1βv2βX1βX2β and h12βv2βX1βX2β are not hit by differentials since
ExtA2β0,β8β(Z2β,C1βββC1ββ)=0 by Theorem 5.7.
We obtain the following.
Theorem 5.19**.**
In grading β₯10, there is an isomorphism of graded abelian groups
[TABLE]
where β£yβ£=12, β£Xiββ£=8, β£Zβ£=16, β£v1ββ£=β2, and β£v2ββ£=β6. Here
Inβ=ker(Fnβ@>Ο΅>>Z), where Fnβ is a free abelian group with basis {X1iβX2nβiβ:1β€i<n}, and
Ο΅(X1iβX2nβiβ)=1.
Thus Inβ consists of all polynomials of grading n with sum of coefficients equal to 0. We could have
extended the description in 5.19 down to grading 8, but the description would have been slightly more complicated,
since it would include h1βv2βZ and h12βv2βZ.
The motivation for this section was to see if perhaps
[TABLE]
might
be something nice like the I(X1ββX2β) which was the case for BPβ(β). In Theorem 5.19, we described
tmfβ(CPββ§CPβ). To obtain tmfβ(CPβΓCPβ), we add on two copies of
tmfβ(CPβ), which was described in 5.15. Denote by Z1β and Z2β the generators in
tmf16(CPβΓCPβ). Monomials Z1iβZ2nβiβ should equal Zn of 5.19 plus perhaps
elements of I2nβ of 5.19. The class y of 5.19 plus perhaps a sum of elements of higher
filtration is in ker(dβ) and not in the ideal generated by (Z1ββZ2β). Thus, as expected, ker(dβ) does
not have the nice form that it did for BPβ(β), and so we cannot use this argument to show that the axial class in tmfβ(RPβΓRPβ) is u(X1ββX2β). However, we showed something like this by a completely different method in Theorem
4.10. We feel that
the results obtained in Theorems 5.15 and 5.19 should be
of independent interest.
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