Number of moduli of irreducible families of plane curves with nodes and cusps
Concettina Galati

TL;DR
This paper investigates the moduli of irreducible plane curves with nodes and cusps, establishing bounds and constructing examples with expected moduli and non-positive Brill-Noether number.
Contribution
It provides bounds on the number of moduli for families of such curves and constructs examples achieving the expected number of moduli with specific singularity conditions.
Findings
Bounds on the number of moduli for families of plane curves with nodes and cusps.
Construction of examples with expected moduli and non-positive Brill-Noether number.
Abstract
Consider the family S of irreducible plane curves of degree n with d nodes and k cusps as singularities. Let W be an irreducible component of S. We consider the natural rational map from W to the moduli space of curves of genus g=(n-1)(n-2)/2-d-k. We define the "number of moduli of W" as the dimension of the image of W with respect to this map. If W has the expected dimension equal to 3n+g-1-k, then the number of moduli of W is at most equal to the min(3g-3, 3g-3+\rho-k), dove \rho is the Brill-Neother number of the linear series of degree n and dimension 2 on a smooth curve of genus g. We say that W has the expected number of moduli if the equality holds. In this paper we construct examples of families of irreducible plane curves with nodes and cusps as singularities having expected number of moduli and with non-positive Brill-Noether number.
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Taxonomy
TopicsAlgebraic Geometry and Number Theory · Advanced Algebra and Geometry · Analytic Number Theory Research
Number of moduli of irreducible families of plane curves with
nodes and cusps.
Concettina Galati
Dipartimento di Matematica, Università degli Studi della Calabria, via P. Bucci, cubo 30B, Arcavacata di Rende (CS)
(Date: 06 September 2005)
Abstract.
Let be the family of irreducible plane curves of degree with nodes and cusps as singularities. Let be an irreducible component. We consider the natural rational map
[TABLE]
from to the moduli space of curves of genus . We define the number of moduli of as the dimension . If has the expected dimension equal to , then
[TABLE]
where is the Brill-Neother number of the linear series of degree and dimension on a smooth curve of genus . We say that has the expected number of moduli if the equality holds in (1). In this paper we construct examples of families of irreducible plane curves with nodes and cusps as singularities having expected number of moduli and with non-positive Brill-Noether number.
Key words and phrases:
families of plane curves, number of moduli, nodes and cusps.
1991 Mathematics Subject Classification:
14H15; 14H10; 14B05
1. Introduction
In this paper we compute the number of moduli of certain families of irreducible plane curves with nodes and cusps as singularities. Let , with , be the closure, in the Zariski’s topology, of the locally closed set of reduced and irreducible plane curves of degree with cusps and nodes. Let be an irreducible component of the variety . We denote by the open set of of points such that is smooth at and such that corresponds to a reduced and irreducible plane curve of degree with nodes, cusps and no further singularities. Since the tautological family , parametrized by , is an equigeneric family of curves, by normalizing the total space, we get a family
[TABLE]
of smooth curves of genus . Because of the functorial properties of the moduli space of smooth curves of genus , we get a regular map , sending every point to the isomorphism class of the normalization of the plane curve corresponding to the point . This map extends to a rational map
[TABLE]
We say that is the moduli map of and we set
[TABLE]
Notice that, when is reducible, two different irreducible components of can have different number of moduli. We say that has general moduli if is dominant. Otherwise, we say that has special moduli.
Definition 1.1**.**
When has the expected dimension equal to and , we say that has the expected number of moduli if
[TABLE]
where is the number of Brill-Noether of the linear series of degree and dimension on a smooth curve of genus .
As we shall see in the next section, when and when has the expected dimension equal to , the number of moduli of is at most equal to the expected one. This happens in particular if . If , in general we have not an upper-bound for the dimension of and we cannot provide an upper bound for the number of moduli of , (see lemma 2.2 and remark 2.3). Moreover, by classical Brill-Neother theory when is positive and by a well know result of Sernesi when (see [18]), we have that , (which is irreducible by [8]), has the expected number of moduli for every . When there are known results giving sufficient conditions for the existence of irreducible components of with general moduli, (see propositions 2.5 and 2.6 and corollary 2.7). In this article we construct examples of families of irreducible plane curves with nodes and cusps with finite and expected number of moduli. A large part of this paper is obtained working out the main ideas and techniques that Sernesi uses in [18].
In section 2.1 we introduce the varieties and we recall their main properties. In section 2.2 we discuss on definition 1.1 and we summarize known results on the number of moduli of families of irreducible plane curves with nodes and cusps. In theorem 3.5 we prove the existence of plane curves with nodes and cusps as singularities whose singular points are in sufficiently general position to impose independent linear conditions to a linear system of plane curves of a certain degree. This result is related to the moduli problem by lemma 3.2, remark 3.4 and proposition 4.1, where we find sufficient conditions in order that an irreducible component has the expected number of moduli. If verifies the hypotheses of proposition 4.1, then the Brill-Neother number is not positive and has finite number of moduli. Moreover, by lemma 4.6 and corollary 4.7, for every and , there is at least an irreducible component , such that and the general element corresponds to a plane curve verifying hypotheses of proposition 4.1 and so having the expected number of moduli. Finally, the main result of this paper is contained in theorem 4.9, where, by using induction on the degree and on the genus of the general curve of the family, we construct examples of families of irreducible plane curves with nodes and cusps verifying the hypotheses of proposition 4.1. In particular, we prove that, if and , then has at least an irreducible component which is not empty and which has the expected number of moduli. This result may be improved and examples of families of curves showing that the condition is not sharp are given in remark 4.10. Notice that the previous theorem provides only examples of families of plane curves with nodes and cusps with expected number of moduli, when is not positive. When the number of cusps is very small, we expect it is possible to prove the existence of irreducible components of with expected number of moduli, for every value of . For example, from a result of Eisenbud and Harris, it follows that , (which is irreducible by [16]), has general moduli if , (see corollary 2.7). In theorem 4.11, by using induction on we find that has general moduli also when . By recalling that, by theorem 4.9, has expected number of moduli when , we conclude that has the expected number of moduli for every or, equivalently, for every . We still don’t know examples of irreducible components of having number of moduli smaller that the expected.
2. Preliminaries
2.1. On Severi-Enriques varieties
We shall denote by the Hilbert scheme of plane curves of degree , by the point parametrizing a plane curve and by the closure, in the Zariski topology, of the locally closed set parametrizing reduced and irreducible plane curves of degree with nodes and cusps as singularities. These varieties have been introduced at the beginning of the last century by Severi and Enriques. In particular, the case has been studied first by Severi and for this reason the varieties are usually called Severi varieties, while for the varieties are called Severi-Enriques varieties. We recall that every irreducible component of has dimension at least equal to
[TABLE]
where . When the equality holds we say that has expected dimension. Moreover, it is well known that if then every irreducible component of has expected dimension, (see for example [23] or [25]). On the contrary, when , there exist examples of irreducible components of having dimension greater than the expected, (see [25]). Moreover, we recall that is not empty for every and it contains in its closure all points parameterizing irreducible plane curves of degree and genus , (see [24], [25] and [1]). Often, we shall denote by . While the proof of the existence of is quite elementary and it is due to Severi, the irreducibility of remained an open problem for a long time and it has been proved by Harris only in 1986. Later, by using the same techniques of Harris, Kang has proved the irreducibility of with , see [8] and [16]. However, in general, is reducible and there exist values of , and such that is empty, (see [25], [12], [20], [11] or chapter 2 of [7] and related references). Finally, we recall that, if is a non-empty irreducible component of the expected dimension equal to , then, for every and , there exists a non-empty irreducible component such that . This happens in particular if . More precisely, it is true that, if is a reduced (possibly reducible) plane curve of degree with cusps at points , nodes at points and no further singularities, then, chosen arbitrarily cusps, say among the cusps of , cusps among and nodes among the nodes of , there exists a family of reduced plane curves of degree , whose special fibre is and whose general fibre has a node in a neighborhood of every marked node of , a cusp in a neighborhood of each point , a node in a neighborhood of each point and no further singularities, (see [25], corollary 6.3 of [11] or lemma 3.17 of chapter 2 of [7]). To save space, we shall say that the family is obtained from by preserving the singularities and , by deforming in a node each cusp and by smoothing the other singularities.
2.2. Known results on the number of moduli of
In order to explain the definition 1.1, we need to recall some basics of Brill-Noether theory. Given a smooth curve of genus , the set of linear series on of dimension and degree , is a projective variety which verifies the following properties:
- (1)
is not empty of dimension at least , if , (see theorem V.1.1 and proposition IV.4.1 of [4]). 2. (2)
Let be a given linear series, let be a divisor and let be the three dimensional vector space corresponding to . Denoting by the canonical sheaf of and by
[TABLE]
the natural multiplication map, also called the Brill-Noether map of the pair , we have that the dimension of the tangent space to at the point ,corresponding to , is equal to
[TABLE]
(see [2] or proposition IV.4.1 of [4] for a proof). 3. (3)
Moreover, if is a curve with general moduli (i.e. if varies in an open set of ), the variety is empty if , it consists of a finite number of points if and it is reduced, irreducible, smooth and not empty variety of dimension exactly , when , (see theorem V.1.5 and theorem V.1.6 of [4]). In the latter case, the general on defines a local embedding on and it maps to as a nodal curve, (see theorem 3.1 of [1] or lemma 3.43 of [9]).
From (3), we deduce that, the Severi variety of irreducible plane curves of genus , has general moduli when and it has special moduli when . When , and then , by definition 1.1, we expect that the image of into has codimension exactly . Equivalently, recalling that, in this case,
[TABLE]
we expect that on the smooth curve , obtained by normalizing the plane curve corresponding to the general element of , there is only a finite number of mapping to the plane as a nodal curve. This is a well known result proved by Sernesi in [18].
Theorem 2.1** (Sernesi, [18]).**
The Severi variety of irreducible plane curves of degree and genus has number of moduli equal to
[TABLE]
What can we say about the number of moduli of an irreducible component of , when ? In this case we need to distinguish the two cases and . In the first case we have the following result.
Lemma 2.2**.**
For every not empty irreducible component of , with and , the number of moduli of is at most equal to
[TABLE]
where is the Brill-Neother number of moduli of linear series of dimension and degree on a smooth curve of genus .
Proof.
We recall that an ordinary cusp of a plane curve corresponds to a simple ramification point of the normalization map , i.e. to a simple zero of the differential map . If we denote by the set of on defining a birational morphism with simple ramification points, then is a locally closed subset of and every irreducible component of has dimension at least equal to , if it is not empty. In particular, if is the variety whose points correspond to the pairs where and is a frame of the three dimensional space associated to the linear series , then every irreducible component of has dimension at least equal to
[TABLE]
Now, let be one of the irreducible components of and let be a general point of . Then, if is the corresponding plane curve and is the normalization map, then the fibre over the point of the moduli map
[TABLE]
consists of an open set in one or more irreducible components of . In particular, every irreducible component of the general fibre of has dimension at least equal to . Moreover, if then has the expected dimension equal to , (see [25] or [23]). Finally, if , then
[TABLE]
This proves the statement. ∎
Remark 2.3**.**
The proof of the previous lemma still holds if but has the expected dimension. However in general, when , we don’t have a bound for . Indeed, in this case the dimension of the general fibre of the moduli map of is still at least equal to , but may have dimension larger than . Anyhow, by the following proposition, every not empty irreducible component of has special moduli if .
Proposition 2.4** (Arbarello-Cornalba, [1]).**
Let be a general curve of genus and let be a birational morphism, then the degree of the zero divisor of the differential map of is smaller than . In particular, every irreducible component of has special moduli if .
A sufficient condition for the existence of irreducible families of plane curves with nodes and cusps with general moduli is given by the following result.
Proposition 2.5** (Kang, [15]).**
* is irreducible, not empty and with general moduli if , where .*
Actually, in [15], Kang proves that if , then is not empty and irreducible. But from his proof it follows that, under the hypothesis of proposition 2.5, has general moduli because the general element of corresponds to a curve which is a projection of an arbitrary smooth curve of genus in , from a general -plane intersecting the tangent variety of in different points. Another result which may be used to find examples of families of plane curves with nodes and cusps having general moduli is the following. Let be a linear series on associated to a -space , where is an invertible sheaf on , and let be a basis of , then the ramification sequence of the at is the sequence with Choosing another basis of , the ramification sequence of at doesn’t change. We say that the ramification sequence of the at is at least equal to if , for every , and we write .
Proposition 2.6** (Proposition 1.2 of [10]).**
Let be a general curve of genus , let be a general point on and let be any ramification sequence. There exists a on having ramification at least at if and only if
[TABLE]
where .
From proposition 2.6, we easily deduce the following result.
Corollary 2.7**.**
Suppose that and . Then is not empty, irreducible and it has general moduli.
Proof.
By [16], the variety is irreducible for every and . Moreover, by using classical arguments, one can prove that is not empty if and , (see, for example, corollary 3.18 of chapter two of [7]). Finally, by theorem 1.1 of [21], by using the terminology of proposition 2.6, under the hypothesis , in particular if , the variety contains every point of corresponding to a plane curve of genus such that the normalization morphism of has at least a ramification point with ramification sequence . Then, by proposition 2.6, if and , the moduli map of is surjective. ∎
3. On the existence of certain
families of plane curves with nodes and cusps in sufficiently general position
As we already observed, we don’t have a complete answer for the existence problem of . In this section we are interested in a little more specific existence problem. We shall prove the existence of plane curves with nodes and cusps as singularities whose singular points are in sufficiently general position to impose independent linear conditions to a linear system of plane curves of a certain degree.
Definition 3.1**.**
A projective curve is said to be geometrically -normal if the linear series cut out on the normalization curve of by the pull-back to of the linear system of hypersurfaces of of degree is complete.
From a geometric point of view, a projective curve is geometrically - normal if and only if the image curve of by the Veronese embedding of degree , is not a projection of a non-degenerate curve living in a higher dimensional projective space. We shall say that a curve is geometrically linearly normal (g.l.n. for short) if it is geometrically 1-normal. Every such a curve is not a projection of a curve lying in a projective space of larger dimension.
The following result is proved under more general hypotheses in [5], theorem 2.1.
Lemma 3.2**.**
Let be an irreducible and reduced plane curve of degree and genus with at most nodes and cusps as singularities. Let be an integer such that , then is geometrically -normal if and only if it is smooth. On the contrary, if , the plane curve is geometrically -normal if and only if its singular points impose independent linear conditions to plane curves of degree .
We recall the following classical definition.
Definition 3.3**.**
Let be a plane curve of degree with nodes at and cusps at as singularities. Let be the normalization of . The adjoint divisor of is the divisor on defined by .
Proof of lemma 3.2..
Let be a plane curve as in the statement of the lemma. Then, is geometrically -normal if and only if, by definition,
[TABLE]
where is the ideal sheaf of in and , where is the general line of . By Riemann-Roch theorem, is geometrically -normal if and only if
[TABLE]
where is the geometric genus of and is the canonical sheaf of . On the other hand, it is well known that , where is the adjoint divisor of , (see definition 3.3 and [4], appendix A). If then and is geometrically -normal if and only if
[TABLE]
where . This equality is verified if and only if , i.e. is smooth. If , and (2) is verified if and only if
[TABLE]
On the other hand, if is the blowing-up of the plane at the singular locus of , denoting by the pullback of the singular locus of with respect to and by the sheaf , we have that
[TABLE]
where is the ideal sheaf of singular points of . ∎
Remark 3.4**.**
Notice that, if an irreducible and reduced plane curve of degree with only nodes and cusps as singularities is geometrically -normal, with , then it is geometrically -normal for every . Indeed, if a set of points imposes independent linear conditions to a linear system , then it imposes independent linear conditions to every linear system containing .
Theorem 3.5**.**
Let be the variety of irreducible and reduced plane curves of degree with nodes and cusps. Suppose that , , and are such that
[TABLE]
where is the integer part of . Then the variety is not empty and there exists at least an irreducible component whose general element corresponds to a geometrically -normal plane curve.
Remark 3.6**.**
As we shall see in the next section, (see proposition 4.1), the geometric linear normality of the plane curve corresponding to the general element of an irreducible component of , is related with the number of moduli of . Another motivation for the previous theorem has been the family of irreducible plane sextics with six cusps. By [25], we know that contains at least two irreducible components and . The general point of corresponds to a sextic with six cusps on a conic, whereas the general element of corresponds to a sextic with six cusps not on a conic. Note that, by the previous lemma the general element of parameterizes a geometric linearly normal sextic, unlike the general element of , which corresponds to a projection of a canonical curve of genus four. Theorem 3.5, proves in particular that, under a suitable restriction, (see inequality (3)), on the genus of the curve corresponding to the general element of the family and, if the number of the cusps is small, the variety contains a not empty irreducible component whose general element corresponds to a curve which is not a projection of an other curve, lying in a projective space of larger dimension. We notice that the inequality (3) of the previous theorem can’t be improved. Indeed, if , then if and only if . On the other hand, by using the same notation as in theorem (3.5), if , then, by Riemann-Roch theorem, we have that On the contrary, inequalities (5) and (6) are not sharp, (see example 3.7).
In the case of and , theorem 3.5 has been proved by Sernesi in [18], section 4. The case and is already contained in [5]. To show theorem 3.5, we proceed by induction on the degree and on the number of nodes and cusps of the curve. The geometric idea at the base of the induction on the degree of the curve is, mutatis mutandis, the same as that of Sernesi.
Proof of theorem
3.5..
Let be a positive integer such that and let be an irreducible component of . By standard semicontinuity arguments it follows that, if there exists a point corresponding to a geometrically -normal curve with only cusps and nodes as singularities, then the general element of corresponds to a geometrically -normal plane curve. Moreover, if the theorem is true for fixed , , as in (5) or in (6) and as in (3), then the theorem is true for , and any and . Indeed, from the hypotheses (3), (5) and (6), it follows in particular that . By section 2.1, under this hypothesis, for every and for every , there exists a family of plane curves of degree , parametrized by a curve , whose special fibre is and whose general fibre has nodes and cusps as singularities. The statement follows by applying the semicontinuity theorem to the family , obtained by normalizing the total space of the pull-back family of to the normalization curve of . Finally, it’s enough to show the theorem when the equality holds in (5), (6) and (3).
First of all we consider the case . We will show the statement for any fixed and by induction on . Let, then and . In this case the equality holds in (3) if Since one point imposes independent linear conditions to regular functions, by using lemma 3.2, we find that every irreducible plane curve of degree with one node and no further singularities is geometrically -normal. So, the first step of the induction is proved. Suppose, now, that the theorem is true for and let be a point corresponding to a geometrically -normal curve with nodes. Let be a line which intersects transversally and let be marked points of . If , then are nodes for . Let be the normalization of and the partial normalization of , obtained by smoothing all singular points of , except . We have the following exact sequence of sheaves on
[TABLE]
where and is the pull-back with respect to of general line of . Since we get that
[TABLE]
and so
[TABLE]
Now, by section 2.1, we can obtain as the limit of a -parameter family of irreducible plane curves
[TABLE]
of degree with
[TABLE]
nodes specializing to nodes of different from the marked points . Moreover, one can prove that is smooth, (see [24] or [25]). Normalizing , we obtain a family whose general fibre is smooth and whose special fibre is exactly , and we conclude the inductive step by (8) and by semicontinuity theorem.
Now we consider the case or and as in (5) and in (6). Suppose the theorem is true for and let be a general point in one of the irreducible components of . Then, let be a smooth plane curve of degree if or an irreducible cubic with a cusp if . By the generality of , we may suppose that intersects transversally. Let be fixed points of . If , then are nodes for . Let be the normalization of and the partial normalization of , obtained by smoothing all singular points except . By using the same notation and by arguing as before, from the following exact sequence of sheaves on
[TABLE]
we deduce that
[TABLE]
Now, by section 2.1, we can obtain as limit of a family of irreducible plane curves
[TABLE]
of degree with nodes specializing to nodes of different to , and cusps specializing to cusps of . We conclude by (9) and by semicontinuity, as before. Now we have to show the first step of the induction. For the induction begins with the cases . Trivially, if and one point imposes independent conditions to the linear system of regular functions. If and we have to show that there are irreducible quintics with three cusps not on a line. A quintic with three cusps is a projection of the rational normal quintic from a plane generated by three points lying on three different tangent lines to . By Bezout theorem the three cusps of such a plane curve can’t be aligned. If , one can repeat the classical argument used by Zariski, see [24] or example 3.20 of chapter 2 of [7]. For we have to show the theorem for , while for we have to show the theorem for . The case and is trivial. When , and we have that . To show that there exists an irreducible sextic with three cusps not on a line, consider a rational quartic with three cusps, (see corollary 3.18 of chapter 2 of [7] for the existence). By Bezout theorem, the three double points of can’t be aligned. Then consider a sextic which is union of and a conic which intersects transversally. By section 2.1, one can smooth the intersection points of and obtaining a family of sextics with three cusps not on a line. For , and we argue as in the previous case, by using a sextic with six cusps not on a conic and a line with intersects transversally. Similarly for , and and and ∎
Example 3.7**.**
Inequalities (5) and (6) are not sharp. To see this, we can consider the example of curves of degree . We recall that we say that a plane curve is geometrically linearly normal (g.l.n. for short) if it is geometrically -normal. Theorem 3.5 ensures the existence of g.l.n. irreducible plane curves of degree with cusps and nodes as singularities. But, by using the same ideas as we used in theorem 3.5, one can prove the existence of g.l.n. plane curves of degree with nodes and cusps. It is enough to consider a sextic with six cusps not on a conic and a rational quartic with three cusps intersecting transversally. We choose five points of . If and are the normalization curves of and respectively and is the partial normalization of obtained by normalizing all its singular points except , by considering the following exact sequence
[TABLE]
we find that . By using terminology of section 2.1, the statement follows by smoothing the singular points of , and by semicontinuity, as in the proof of theorem 3.5. The bound on the number of cusps of theorem 3.5 can be improved also for or . For example, theorem 3.5 ensures the existence of geometrically -normal curves of degree with and nodes as further singularities. But, by considering a geometrically -normal curve of degree with six cusps and a quartic with cusps and arguing as before, we can find geometrically -normal irreducible plane curves of degree with nodes and cusps.
4. Families of plane curves with nodes and
cusps with finite and expected number of moduli.
Let be an irreducible component of . We want to give sufficient conditions for to have the expected number of moduli. Let be a general element, corresponding to a plane curve with normalization map . We shall denote by the canonical sheaf of and by the sheaf associated to the pullback to of the divisor cut out on from the general line of .
Proposition 4.1**.**
Let be an irreducible component of and let be a general element, corresponding to a plane curve with normalization map . Suppose that is smooth of the expected dimension equal to at . Moreover, suppose that:
- (1)
* is geometrically linearly normal, i.e. ,* 2. (2)
the Brill-Noether map
[TABLE]
is surjective.
Then has the expected number of moduli equal to .
Proof.
The case has been proved by Sernesi in [18], section 4. We shall assume . Let be a plane curve verifying the hypotheses of the proposition. By lemma 1.5.(b) of [22], the hypothesis that is smooth of the expected dimension at implies the vanishing , where if the normal sheaf of . We recall that, denoting by and the tangent sheaf of and respectively, then the normal sheaf of is defined as the cokernel of the differential map of
[TABLE]
By theorem 3.1 of [13], the vanishing is a sufficient condition for the existence of a universal deformation family
[TABLE]
of the normalization map , whose parameter space is smooth at the point [math] corresponding to , with tangent space at [math] equal to . On the contrary, by [3], p. 487, the Severi variety of irreducible plane curves of genus is singular at the point and the universal deformation space of is a desingularization of at . Moreover, by corollary 6.11 of [2], if is the locus of points of corresponding to a morphism with ramification points, then the tangent space to at [math] is a subspace of of codimension such that , where is the torsion subsheaf of . By [3], p.487, it follows that, if
[TABLE]
is the natural -map from to , then the differential map
[TABLE]
restricts to an isomorphism between and the tangent space to at .
We can now go back to the number of moduli of . From the exact sequence (10), by using that , we get the following long exact sequence
[TABLE]
Recalling that the space is canonically identified with the tangent space to at the point associated to the normalization of , the coboundary map sends the Horikawa class of an infinitesimal deformation of to the Kodaira-Spencer class of the corresponding infinitesimal deformation of . So, is the differential map at the point of the moduli map Since the point is general in , and recalling the isomorphism , we have that
[TABLE]
Now, from the exact sequence (10), we have that
[TABLE]
Moreover, from the pull-back to of the Euler exact sequence, we deduce the well known isomorphism
[TABLE]
and we conclude that
[TABLE]
Notice that the previous equality is always true, even if doesn’t verify the hypothesis or of the statement. Moreover, if is geometrically linearly normal, i.e. if , we have that
[TABLE]
When is surjective, and
[TABLE]
Since the dimension of the fibre of the moduli map
[TABLE]
has dimension at least equal to , from (12) we deduce that the differential map of has maximal rank at [math] and, in particular, we have that . Equivalently, there exist only finitely many on . It follows that there are only finitely many on mapping to the plane as a curve with cusps and nodes. Then,
[TABLE]
∎
Remark 4.2**.**
Arguing as in the proof of the previous proposition, it has been proved in [18] that, if is a geometrically linearly normal plane curve with only nodes as singularities and the Brill-Noether map of the normalization morphism of is injective, then has general moduli. If and verify the hypotheses of proposition 4.1 but we assume that is injective, we may only conclude that is dominant with surjective differential map at . So . But this is not useful to compute the dimension of . However, in this case we get that
[TABLE]
Then, by using that and by recalling that if has the expected dimension then the number of moduli of is at most the expected one (see lemma 2.2 and remark 2.3), we find that
[TABLE]
Remark 4.3**.**
*Notice that, if a plane curve of genus verifies the hypotheses (1) and (2) of the previous proposition, then the Brill-Noether number is not positive and, in particular, . We don’t know examples of complete irreducible families with the expected number of moduli whose general element corresponds to a curve of genus , with , which doesn’t verify properties (1) and (2). *
Lemma 4.4** ([5], Corollary 3.4).**
Let be an irreducible plane curve of degree with only nodes and cusps as singularities and let be the normalization morphism of . Suppose that is geometrically -normal, i.e. . Then the Brill-Noether map
[TABLE]
is surjective.
Proof.
By lemma 3.2, the curve is geometrically -normal if and only if the scheme of the singular points of imposes independent linear conditions to the linear system of plane curves of degree . Since , imposes independent linear conditions plane curves of degree , and, by using lemma 3.2, we get that , i.e. is geometrically linearly normal. Now, denote by the ideal sheaf of . Notice that the curve is geometrically 2-normal if and only if the ideal sheaf is [math]-regular, (in the sense of Castelnuovo-Mumford). Indeed, since , the ideal sheaf is [math]-regular if and only if . Because of the [math]-regularity of , we have the surjectivity of the natural map
[TABLE]
(see [17]). Finally, by the geometric linear normality of , the vertical maps of the following commutative diagram
[TABLE]
are surjective and, hence, the Brill-Noether map is surjective too. ∎
Corollary 4.5**.**
Let be an irreducible component of of dimension equal to , such that the general point corresponds to a geometrically -normal plane curve. Then has the expected number of moduli equal to .
Proof.
It follows from proposition 4.1 and lemma 4.4. ∎
In order to produce examples of families of irreducible plane curves with nodes and cusps with the expected number of moduli, we study how increases the rank of the Brill-Noether map by smoothing a node or a cusp of the general curve of the family, (in the sense of section 2.1).
Let , with , be an irreducible component of , let be a general point of and let be the normalization of . Choose a singular point and denote by the partial normalization of obtained by smoothing all singular points of , except the point . If is the dualizing sheaf of and
[TABLE]
is the natural multiplication map, we have the following result.
Lemma 4.6**.**
If and the geometric genus of is such that , with , then . In particular, if , and is surjective, then is also surjective.
Proof.
Let be the normalization map.
[TABLE]
We recall that, if we set when is a node and when is a cusp, then the dualizing sheaf of is a subsheaf of , (see for example [10], p.80). In particular we have the following exact sequence
[TABLE]
where is the skyscraper sheaf on with support at . From this exact sequence, we deduce that
[TABLE]
Moreover, tensoring (13) by , we find the exact sequence
[TABLE]
from which we get an injective map On the other hand
[TABLE]
and so
[TABLE]
Moreover, from the hypothesis , we have that . Therefore, in the following commutative diagram
[TABLE]
where we denoted by the natural multiplication map, the vertical maps are isomorphisms. In particular,
[TABLE]
In order to compute the rank of , we consider the following commutative diagram
[TABLE]
where the vertical maps are injections. Notice that, since we supposed , and , the sheaf is special. We deduce that is not hyperelliptic and, chosen a basis of , the associated map is an embedding. On the contrary, the sheaf does not define an embedding on . Choosing a basis of and denoting by the associated map, this will be an embedding outside . If is a node of and , the image of to , with respect to , will have a node at the image point of and . If is a cusp, then will have a cusp at the image point of . The hyperplanes of passing through cut out on the canonical linear series Moreover, if we denote by the subspace which is the base locus of the hyperplanes of corresponding to , then . Indeed, intersects the curve in the image of the base locus of , which coincides with the base locus of , since is base point free. Now, by (15),
[TABLE]
Then does not belong to the base locus of , and so
[TABLE]
Finally, we find that
[TABLE]
∎
Corollary 4.7**.**
Let be a non-empty irreducible component of the expected dimension of , with . Suppose that has the expected number of moduli and that the general element corresponds to a g.l.n. plane curve of geometric genus such that, if is the normalization of , then the map is surjective. Then, for every and , there is at least an irreducible component , such that , the general element corresponds to a g.l.n. plane curve of geometric genus with normalization and the Brill-Noether map surjective. In particular, has the expected number of moduli.
Proof.
Let be the curve corresponding to the general element of . Since by hypothesis is smooth of the expected dimension at , by section 2.1, for every and for every there exists an irreducible component of containing . In order to prove the statement, it is enough to show it under the hypotheses and , and or and . If and , then the statement follows by standard semiconinuity arguments. If and or and , the statement follows by lemma 4.6 and by standard semicontinuity arguments. ∎
The following lemma has been stated and proved by Sernesi in [18]. Actually, Sernesi supposes that has only nodes as singularities. But, since his proof works for plane curves with any type of singularities and, since we need it for curves with nodes and cusps, we state the lemma in a more general form.
Lemma 4.8**.**
([18], lemma 2.3) Let be an irreducible and reduced plane curve of degree with any type of singularities. Denote by the normalization of . Suppose that and the Brill-Noether map
[TABLE]
has maximal rank. Let be a general line and let , and be three fixed points of . We denote by the partial normalization of , obtained by smoothing all the singular points, except , and . Then and, denoting by the dualizing sheaf of , the multiplication map
[TABLE]
has maximal rank.
Theorem 4.9**.**
Let be the algebraic system of irreducible plane curves of degree with cusps, nodes and geometric genus . Suppose that:
[TABLE]
and
[TABLE]
[TABLE]
Then has at least an irreducible component which is not empty and such that, if is the curve corresponding to the general element of and is the normalization curve of , then and the map has maximal rank. In particular, when , the algebraic system has the expected number of moduli equal to .
Proof.
Suppose that (17) holds. Then, by observing that
[TABLE]
and by using theorem 3.5 for , we have that there exists an irreducible component of whose general element is a geometrically -normal plane curve . By remark 3.4, it follows that also the linear systems cut out on by the conics and the lines are complete. The statement follows from corollary 4.5.
In order to prove the theorem under the hypothesis (18), we consider the following subcases:
- (1)
, i.e. and , 2. (2)
and , 3. (3)
and .
Suppose that (1) holds. By theorem 3.5 for , we know that, under this hypothesis, there exists a nonempty component , whose general element is geometrically -normal. We conclude as in the previous case, by corollary 4.5.
Now, suppose that and verify (2). We shall prove the theorem by induction on and . Set , with fixed. Suppose that the theorem is true for the pair , with . We shall prove the theorem for , observing that . Let be a g.l.n. irreducible plane curve of degree and genus with cusps, nodes and no more singularities. Let be the normalization of . Suppose that the Brill-Noether map has maximal rank. Let be a general line and let , and be three fixed points of . By section 2.1, since , one can smooth the singular points and preserve the other singularities of , obtaining a family of plane curves whose general fibre is irreducible, has degree and genus . We conclude by lemma 4.8 and by standard semicontinuity arguments.
Now we prove the first step of the induction for . If , we get . Let , i.e. . Let be a g.l.n. irreducible plane curve of degree , of genus with cusps and nodes as singularities, such that no seven singular points of lie on an irreducible conic. To prove that there exists such a plane curve, notice that, by applying theorem 3.5 for , we get that, for any fixed , there exists a g.l.n. irreducible sextic of genus four with cusps and nodes. Let be the singular points of . Since the points of impose independent linear conditions to the conics, however we choose five singular points of , with , there exists only one conic , passing through these points. Let us set and let be a line intersecting transversally at six points out of . By Bezout theorem, no seven singular points of belong to an irreducible conic. Moreover, if is the normalization of , if are four fixed points of and is the partial normalization of obtained by smoothing the singular points except , then, by the following exact sequence
[TABLE]
we find that . By section 2.1, one can smooth the singularities and preserve the other singularities of , getting a family of irreducible septics whose general fibre is a geometrically linearly normal irreducible septic with cusps and nodes such that no seven singular point of belong to an irreducible conic. Let, now, be the normalization of and let be the adjoint divisor of the normalization map . We shall prove that . Since is geometrically linearly normal, we have that
[TABLE]
Then, by the base point free pencil trick, we find that
[TABLE]
where is the base locus of . Let be the pencil of plane cubics passing through the eight double points of and let be the base locus of the pencil . Let be the general element of . Suppose that has dimension one. If contains a line , then, by Bezout theorem, at most three points among , say can lie on and the other points have to be contained in the base locus of a pencil of conics . Using again Bezout theorem, we find that the curves of are reducible and the base locus of contains a line . But also contains at most three points of . It follows that there is only one cubic through . This is not possible by construction. Suppose that contains an irreducible conic . By Bezout theorem, at most seven points among may lie on . On the other hand, since , there are exactly seven points of , say , on and the general cubic of is union of and a line passing through . Since, by construction, no seven singular points of lie on an irreducible conic, also in this case we get a contradiction. So the general element of is irreducible. Using again Bezout theorem, we find that is smooth and has only one more base point . We consider the following cases:
a) doesn’t lie on ;
b) lies on , but ;
c) is infinitely near to one of the points , say , i.e. the cubics of have at the same tangent line , but is not contained in the tangent cone to at ;
d) is like in the case c), but is contained in the tangent cone to at .
Suppose that the case a) or c) holds. Thus and
[TABLE]
By Riemann-Roch theorem, . One sees that , by blowing-up the plane at and by using some standard exact sequences. Suppose now that the case b) holds. Thus and
[TABLE]
Also in this case one sees that by blowing-up at and and by using standard exact sequences. Finally, we analyze the case d). Let be the blow-up of the plane at with exceptional divisors . Let be the intersection point of and the strict transform of the general cubic of the pencil . We denote by the blow-up of at and by the composition map of the maps and . We still denote by their strict transforms on , by and the strict transforms of and and by the new exceptional divisor of . In this case we have that , . Moreover, the divisor is cut out on by and the base locus of the linear series coincides with the intersection point of and . So, we have that
[TABLE]
Moreover, from the following exact sequence
[TABLE]
we find that . In order to show that , we consider the following exact sequence
[TABLE]
By Riemann-Roch theorem, we have that
[TABLE]
Moreover, by Serre duality we have that
[TABLE]
From the exact sequence
[TABLE]
by using that the map is surjective and that
, we find that
[TABLE]
Then, by (4), and . The first step of induction for and is proved.
We complete the proof of the first step of the induction, for and verifying (2). When and , the existence of a g.l.n. plane curve follows from theorem 3.5. Using the above notation, if and if . In any case is injective. When and the theorem follows by induction from the case . For and , we find that , or, equivalently, . In theorem 3.5, we proved the existence of geometrically linearly normal plane curves of degree and genus , with nodes and cusps. For every such plane curve , using the above notation, the Brill-Noether map is injective since . The cases and are similar.
Suppose now that and verify (3). First of all we prove the theorem for , , . For and , we find and we argue as in the case and . Similarly, for . For and in theorem 3.5 we proved the existence of geometrically linearly normal plane curves with cusps and nodes as singularities. For every such a plane curve , denoting by its normalization, we get that , i.e. the linear system of conics passing through the four singular points of is a pencil which cuts out on the complete linear series . We have two possibilities: either the general element of this pencil is irreducible or it consists of a line containing exactly three singular points of and a line passing through . In any case the base locus of intersects only at and the linear series has no base points. Then, by the base point free pencil trick , we find that , where is the adjoint divisor of the normalization map . By Riemann-Roch theorem, we have that By blowing-up at , one can see that , as we wanted.
Finally, we show the theorem under the hypothesis (3) for , by using induction on . In order to prove the inductive step we may use lemma 4.8, exactly as we did in the case (2). We prove the first step of induction. If we have that . On pages 2 and 19 we proved the existence of geometrically linearly normal plane curves of degree and genus with , such that, if are the singular points of , then no seven points among lie on a conic. In particular, we proved that, for every such a plane curve , the general element of the pencil of cubics passing through is irreducible and, if is the normalization of , then the Brill-Noether map is injective. Let be the partial normalization of which we get by smoothing all the singular points of except a node, say . By using the same notation and by arguing exactly as in the proof of lemma 4.6, we get the following commutative diagram
[TABLE]
where is the multiplication map and the vertical maps are isomorphisms. We want to prove that the map is surjective. By the previous diagram it is enough to prove that is surjective. Since and
[TABLE]
we have that and is surjective if . By recalling that is geometrically linearly normal, we have that, if is the scheme of the points and is the ideal sheaf of in , then in the following commutative diagram
[TABLE]
the vertical maps are isomorphisms. Hence, it is enough to prove that the kernel of the multiplication map has dimension one. Let be a basis of the vector space . Since the general cubic passing through is irreducible, we may assume that and are irreducible. Suppose, by contradiction, that there exist at least two linearly independent vectors in the kernel of . Then, there exist sections and of such that the sections and are linearly independent in and
[TABLE]
We can look at (22) as a linear system in the variables . The space of solutions of (22) is generated by the vector
[TABLE]
In particular, if we set , we find that , for every . But this is not possible since and are irreducible. We deduce that
[TABLE]
and is surjective. The existence of a plane septic of genus with cusps and nodes as singularities, with injective Brill-Neother map, follows now by smoothing the node (in the sense of section 2.1) and by standard semicontinuity arguments. ∎
Remark 4.10**.**
Notice that the conditions which we found in theorem 4.9 in order that has at least an irreducible component with the expected number of moduli, are not sharp, even if we suppose . To see this, notice that in remark 3.6 we proved the existence of an irreducible component of whose general element corresponds to a -normal plane curve. By remark 3.4 and corollary 4.5, we have that has the expected number of moduli.
Theorem 4.11**.**
* has the expected number of moduli, for every .*
Proof.
First of all, we recall that, by [16], is irreducible for every . Moreover, from theorem 4.9 and from corollary 2.7, we know that is not empty and it has the expected number of moduli if either or . Next we shall prove that, if , then the algebraic system
[TABLE]
has general moduli. Equivalently, we will show that, if is a general point and , then, on the normalization curve of there are only finitely many linear series with at least a ramification point. Notice that, if , then is odd and . We prove the statement by induction on .
If then . Let be the canonical model of a general curve of genus four and let , with be a divisor in a on . This divisor is cut out on by the tangent line to at . The projection of from is a plane quintic of genus four with a cusp. This proves that has general moduli.
Now we suppose that the theorem is true for and we prove the theorem for . Let be the plane curve with a cusp and nodes corresponding to a general point and let be an irreducible conic intersecting transversally. By section 2.1, the point belongs to . In particular, however we choose four points of intersection between and , there exists an analytic branch of , passing through and whose general point corresponds to an irreducible plane curve of degree with a cusp in a neighborhood of the cusp of and a node at a neighborhood of every node of different from . Moreover, is smooth at the point , (see [7], chapter 2). Let
[TABLE]
be the moduli map of . In order to prove that is dominant it is sufficient to show that . By section 2.1, there exist an analytic open sets , with , such that
[TABLE]
Every , with , has irreducible components, passing through and intersecting transversally at , (see [7], chapter 2 or [25]). Moreover, the general point of every irreducible component of , with , corresponds to an irreducible plane curve of degree with a cusp in a neighborhood of the cusp of , a node in a neighborhood of every node of different from and nodes specializing to fixed points among , as specializes to . Now, notice that the moduli map is not defined at the point , but, if is sufficiently small, then the restriction of to extends to a regular function on . More precisely, let be any family of curves, parametrized by a projective curve , passing through the point and whose general point corresponds to an irreducible plane curve of degree of genus with a cusp and nodes as singularities. If we denote by the family of curves obtained from by normalizing the total space, we have that the general fibre of is a smooth curve of genus , corresponding to the normalization of the general fibre of , whereas the special fibre is the partial normalization of , obtained by normalizing all the singular points, except . Then, the map is defined at and it associates to the point the isomorphism class of . Similarly, if is a general point in one of the irreducible components of , with , then is the partial normalization of obtained by smoothing all the singular points except for the nodes of tending to fixed points among as specializes to . It follows that, if we denote by the locus of parametrizing -nodal curves, then , for every , and . In particular, we find that
[TABLE]
In order to compute the dimension of we consider the rational map
[TABLE]
forgetting the rational tail. By the hypothesis that has general moduli and hence is dominant. Moreover, if is the normalization curve of , by the generality of in , we may assume that is general in . We want to show that . In order to see this, we recall that, by the hypothesis that has general moduli, on there exist only finitely many linear series of degree and dimension two, mapping to the plane as curve with a cusp and nodes as singularities. Let be one of these linear series, let be a basis of and the associated morphism. If are four general points of , then the linear system of conics through is a pencil . Let and be two general conics of . We claim that, if and are isomorphisms between and and respectively, then the points are not projectively equivalent to the points . In order to prove this, it is enough to prove that there are at least two conics in the pencil which verify the claim. Let be a conic. If we choose two sets of points and of not projectively equivalent on , we may always find projective automorphisms and such that and , for every . By construction, the conics and belong to the pencil and verify the claim. This implies that the partial normalizations and of and , obtained by smoothing all the singular points except , are not isomorphic. Now, let be a general conic of and let be four general points of , different from . If is a general conic of the pencil , then the partial normalization and of and obtained, respectively, by smoothing all the singular points except and , are not isomorphic. Indeed, since is a general curve of genus , the only automorphism of is the identity. This proves that . In particular, we deduce that
[TABLE]
and
[TABLE]
∎
Remark 4.12**.**
We expect that it is possible to prove that has expected number of moduli for every also when or . By corollary 2.7 and theorem 4.9, is not empty, irreducible and it has expected number of moduli for and . In order to extend theorem 4.11 to the case and one needs to consider a finite number of cases.
Acknowledgment
The results of this paper are part of my PhD-thesis. I would like to express my gratitude to my advisor Prof. C. Ciliberto who initiated me into the subject of algebraic geometry and who provided me many invaluable suggestions. I have also enjoyed and benefited from conversation with many people including F. Flamini, E. Sernesi, L. Chiantini, L. Caporaso and G. Pareschi. Finally, I would like to thank the referee for useful remarks which allowed me to improve the finale version of this paper.
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