On Existence of Boundary Values of Polyharmonic Functions
M. L. Gorbachuk, S. M. Torba

TL;DR
This paper characterizes the boundary behavior of polyharmonic functions inside the unit disk, establishing conditions for their boundary values to exist in hyperfunction spaces.
Contribution
It provides a comprehensive description of boundary values of polyharmonic functions in terms of hyperfunctions and specifies conditions for these boundary values to belong to particular subspaces.
Findings
Boundary values exist in the space of hyperfunctions.
Necessary and sufficient conditions for boundary value belonging to subspaces.
Complete description of polyharmonic functions inside the unit disk.
Abstract
In trigonometric series terms all polyharmonic functions inside the unit disk are described. For such functions it is proved the existence of their boundary values on the unit circle in the space of hyperfunctions. The necessary and sufficient conditions are presented for the boundary value to belong to certain subspaces of the space of hyperfunctions.
Peer Reviews
No public reviews on file for this paper yet. If you reviewed it on a platform where reviews are public (OpenReview, ICLR, NeurIPS, ICML), you can paste yours below so the community can read it here.
Videos
No videos yet. Explain this paper in a talk, walkthrough, or lecture? Add one.
Taxonomy
TopicsDifferential Equations and Boundary Problems · Algebraic and Geometric Analysis · advanced mathematical theories
ON EXISTENCE OF BOUNDARY VALUES OF POLYHARMONIC FUNCTIONS 111Mathematics Subject Classification. Primary 35J30
Key words and phrases. Polyharmonic equation, solution inside of a domain and its boundary value, hyperfunction, Fourier series.
Supported by CRDF and Ukr. Government (Project UM 1-2507-OD-03)
M.L. GORBACHUK and S.M. TORBA
ABSTRACT. In trigonometric series terms all polyharmonic functions inside the unit disk are described. For such functions it is proved the existence of their boundary values on the unit circle in the space of hyperfunctions. The necessary and sufficient conditions are presented for the boundary value to belong to certain subspaces of the space of hyperfunctions.
The purpose of this paper is to find necessary and sufficient conditions for a solution of the equation inside a domain to have a limit on the boundary of the domain in various functional spaces. We consider the simplest situation where a domain is the unit disk . The case of has been investigated during 20th century by a lot of mathematicians (we refer for details to [1 - 5]. The case of was considered in [6]. For an arbitrary the problem of existence of boundary values in the space - is the unit circle) was discussed in [7].
1. Denote by the set of all infinitely differentiable functions on . We say that a sequence converges to , and write , if for every , the sequence converges to uniformly in . Let also be the set of analytic functions on . The convergence in is introduced in the following way: a sequence converges to in if there exists a neighbourhood of in which all the functions converge to uniformly on any compact set from .
For a number we put
[TABLE]
The linear set is a Banach space with respect to the norm
[TABLE]
It is not hard to show that if , then ,
[TABLE]
and the dense continuous embeddings
[TABLE]
hold.
Let and are the spaces of continuous antilinear functionals on (distributions) and (hyperfunctions), respectively (see [8]). In the following, denotes an action of the functional onto . By convergence in (in ) we mean the weak one, that is, if for any , the number sequence converges to .
As , the Fourier coefficients can be determined for . It is known (see e.g. [9]) that
[TABLE]
and one can easily verify that the below assertion is valid.
Proposition 1
The following equivalence relations hold:
[TABLE]
Moreover, the series converges to in the corresponding space. The sequence , whose elements belong to one of the spaces or , converges to in this space if and only if the constants and in the above estimates for do not depend on and for any .
2. A function is called -harmonic in if it satisfies the equation
[TABLE]
Note, that no conditions on the behaviour of near are imposed.
Theorem 1.
In order that a function be -harmonic in , it is necessary and sufficient that the representation
[TABLE]
be admissible, where are uniquely determined by .
Proof. By Proposition 1,
[TABLE]
So the series converges uniformly in the disk of radius and determines an infinitely differentiable function there. The direct check shows that the functions satisfy (1) in . Since is arbitrary, these functions are solutions of the equation (1) inside .
To prove the necessity, suppose at first . Let be a harmonic function in . Then for a fixed is infinitely differentiable in , and it may be written in the form
[TABLE]
where the series and all its derivatives converge uniformly in . The coefficients are infinitely differentiable on [0, 1) and satisfy the equation
[TABLE]
Hence,
[TABLE]
It follows from the convergence of the series in (3) that
[TABLE]
where is arbitrary. By Proposition 1, are the Fourier coefficients of a certain hyperfunction , and
[TABLE]
Thus, the representation (2) is valid when .
Assume the representation (2) to be true for an -harmonic inside function , and we shall prove that such a representation holds for an -harmonic function.
If is an -harmonic function, then is an -harmonic one. By assumption, there exist such that
[TABLE]
If we choose so that
[TABLE]
then, because of (4), we shall have
[TABLE]
Let us find at first in the case where the equation (5) is of the form
[TABLE]
By using the identity
[TABLE]
for , one can verify that the function , where
[TABLE]
, satisfies (6). Set . By Proposition 1, . So, in the case under consideration
[TABLE]
Suppose now that we know solutions of the equations
[TABLE]
for all is fixed. We show how to find a solution of the equation
[TABLE]
We put
[TABLE]
It follows from (7) and (8) that if is a solution of (9), then
[TABLE]
[TABLE]
[TABLE]
Taking into account that , we conclude, by Proposition 1, that there exists such that
[TABLE]
whence
[TABLE]
where as . By assumption, we can find so that
[TABLE]
Setting
[TABLE]
we arrive at the equality
[TABLE]
It is not hard to observe that for the desired function we have the formula
[TABLE]
[TABLE]
[TABLE]
Then
[TABLE]
where
[TABLE]
Since for
[TABLE]
we have, by Proposition 1, that
[TABLE]
as . The elements are determined uniquely by the function in the following way:
[TABLE]
where the limit is taken in the space . This completes the proof.
Because of harmonicity in of the functions
[TABLE]
the representation (2) implies, in particular, the next assertion (cf. [4]).
Corollary 1.
Let be an -harmonic in function. Then it admits a representation of the form
[TABLE]
where the functions are harmonic in .
When proving the theorem, it was also established the following fact.
Corollary 2.
If is an -harmonic in function, then there exists its radial boundary value on in the space , that is,
[TABLE]
3. Let be a complete linear Hausdorff space such that the continuous embeddings
[TABLE]
hold. We say that is a boundary value on of an -harmonic in function and write if as .
It is seen from Theorem 1 and Corollary 2 that every -harmonic in function has a boundary value in . Moreover, each element is the boundary value of a certain -harmonic in function. The natural question arises: under what conditions on an -harmonic in function its boundary value belongs to ?
Theorem 2.
The boundary value of an -harmonic in function belongs to the space if and only if the set is compact in .
Proof. Necessity. It is known that if , then , and as . Since the embedding is continuous, . By assumption, if . So, the set is compact in .
Sufficiency. Let the set be compact in . Suppose . Then there exists a subsequence such that converges in to a certain element . Since continuously, converges in . Taking into account that as , we have which completes the proof.
In the partial case where , Theorem 2 was obtained in [7]. By using compactness criteria for sets, one can find the sufficient conditions for the boundary value of a polyharmonic function to belong to . For instance, the following assertion is valid.
Corollary 3.
Let be an -harmonic inside the disk function. In order that have a boundary value in , it is necessary and sufficient that:
1) ;
2) \int\limits_{0}^{2\pi}\big{|}u\big{(}re^{i(t-\tau)}\big{)}-u(re^{it})\big{|}^{p}\,dt\to 0\ (\tau\to 0)\mbox{\rm\ uniformly in}\ r\in[0,1).
Now we consider in more detail the case of . Let
[TABLE]
The set with norm forms a Banach space.
Theorem 3.
If is an -harmonic in function, then
[TABLE]
where are taken from representation (2). Moreover, weakly in the space .
Proof. Assume that in the representation (2) . Then
[TABLE]
[TABLE]
Conversely, let . Then, as was shown in [4, Lemma 7], each summand in (10) is bounded, too:
[TABLE]
This is equivalent to the inequality
[TABLE]
that is, .
It still remains to prove the weak convergence of to in . Since as and , we have
[TABLE]
[TABLE]
Thus, weakly in on a total set, and . It follows from here that weakly in . The proof is complete.
Let be a harmonic in function. It follows from (2) that
[TABLE]
In view of , the well-known Fatou lemma and the Lebesgue theorem on passage to the limit yield
[TABLE]
Therefore the weak convergence of to implies the strong one. As was shown in [7], in the case of the boundedness of does not guarantee the convergence of in .
We pass now to the Sobolev spaces
[TABLE]
The following statement is valid.
Theorem 4.
The embeddings
[TABLE]
hold.
Proof. Since the function reaches its maximum at the point , and
[TABLE]
we have
[TABLE]
that is, .
Suppose now . Then, substituting ,
[TABLE]
Multiplying this inequality by and then integrating along , we obtain
[TABLE]
If we put , we get for
[TABLE]
Since
[TABLE]
the relation is fulfilled. Taking in (11) , we conclude that
[TABLE]
that is, , which completes the proof.
The next theorem is devoted to the question on the existence of boundary values in the space of distributions.
Theorem 5.
In order that an -harmonic in function admit a representation of the form (2) with , it is necessary and sufficient that
[TABLE]
Proof. Let the inequality (12) hold. Then for , the function is -harmonic in , and it is not difficult to verify that
[TABLE]
By Theorems 3,4, the function may be represented in the form (2) where . Since , we have .
The necessity of condition (12) for was proved in [5]. Namely, it was shown there that for a harmonic function of the form
[TABLE]
there exists such that
[TABLE]
If we take , where corresponds to from (2), we obtain the estimate (12) for an -harmonic function ( is arbitrary).
Corollary 4.
An -harmonic in function has a boundary value in if and only if it satisfies (12).
For a number we put
[TABLE]
The linear space is endowed with the inductive limit topology of the Banach spaces of functions satisfying (13) with a fixed constant . The norm in is defined as
[TABLE]
It is evident, that
[TABLE]
where denotes the dual of .
Theorem 6.
An -harmonic in function admits a representation of the form (2) with if and only if
[TABLE]
The proof follows the scheme like that in Theorem 5 if to take into account that
[TABLE]
and the series converges to in -topology.
Corollary 5.
In order that an -harmonic in function have a boundary value in the space , it is necessary and sufficiant that the condition (14) be satisfied.
The reference list from the paper itself. Each links out to its DOI / PubMed record.
- 1[1] Privalov I.I. Boundary Properties of Single-Valued Analytic Functions , Gostekhizdat, Moskva-Leningrad, 1950 (in Russian).
- 2[2] Koosis P. Introduction to H p subscript 𝐻 𝑝 H_{p} Spaces , Cambridge University Press, London-New York-New Rochelle-Melburnr-Sydney, 1980.
- 3[3] Gorbachuk V.I., Knyazyuk A.V. Boundary values of solutions of operator differential equations , Uspekhi Mat. Nauk 44 (1989), no. 3, 55-91.
- 4[4] Komatsu H. Ultradistributions and Hyperfunctions , Lecture Notes Math. 287 (1973), 180-192.
- 5[5] Gorbachuk V.I. On solutions of an operator differential equation with singularilies , Boundary Value Problems for Differential Equations, Sborn. Nauchn. Trudov, Inst. Matem. Ukrain. AN, 1992, 8-36.
- 6[6] Gorbachuk M.L., Denche M. Representation and boundary values of biharmonic functions , Uspekhi Mat. Nauk 46 (1991), no. 6, p. 202.
- 7[7] Mikhailov V.P. On the existence of boundary values of solutions of a polyharmonic equation on the boundary of a domain , Mat. Sborn. 187 (1996), no. 11, 89-115.
- 8[8] Berezansky Yu.M., Sheftel Z.G., Us G.F. Functional Analysis. Vol. 1,2 , Birkhauser, Basel-Boston-Berlin, 1966.
