On Equivariant Embedding of Hilbert C^* modules
Debashish Goswami

TL;DR
This paper proves that any Hilbert G-C*-module over an ergodic action of a compact Lie group can be embedded into a trivial module, extending the understanding of equivariant embeddings in operator algebras.
Contribution
It establishes the existence of equivariant embeddings for all Hilbert G-C*-modules under ergodic actions of compact Lie groups, regardless of countable generation.
Findings
Any Hilbert G-C*-module admits an equivariant embedding into a trivial module.
The result applies to modules over ergodic actions of compact Lie groups.
It generalizes previous results to non-countably generated modules.
Abstract
We prove that an arbitrary (not necessarily countably generated) Hilbert - module on a G-C^* algebra admits an equivariant embedding into a trivial module, provided G is a compact Lie group and its action on is ergodic.
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Taxonomy
TopicsAdvanced Operator Algebra Research · Advanced Topics in Algebra · Holomorphic and Operator Theory
**On Equivariant Embedding of Hilbert modules
Debashish Goswami
**
AMS subject classification no. : **46L08
**Key-words : Hilbert modules, Ergodic action, Equivariant triviality, Equivariant embedding.
Abstract
We prove that an arbitrary (not necessarily countably generated) Hilbert - module on a algebra admits an equivariant embedding into a trivial module, provided is a compact Lie group and its action on is ergodic.
1 Introduction
Let be a locally compact group, be a -algebra, and assume that there is a strongly continuous representation . Following the terminology of [6], we introduce the concept of a Hilbert -module as follows :
Definition 1.1
A Hilbert module (or * module* for short) is a pair where is a Hilbert -module and is a map from into the set of -linear (caution : not -linear !) maps from to , such that satisfies the following :
(i) for where is the identity element of ;
(ii) for
(iii) is continuous for each fixed
(iv) for all where denotes the -valued inner product of **
When is understood from the context, we may refer to as a module, without explicitly mentioning the pair Given two modules and , there is a natural -action induced on , given by for is said to be -equivariant if It is clear that for each fixed and , is continuous. We say that is -continuous if is continuous with respect to the norm topology on We say that and are isomorphic as -modules, or that they are equivariantly isomorphic if there is a -equivariant unitary map We call a module of the form (where is some Hilbert space) a trivial module. We say that is *embeddable * if there is an equivariant isometry from to for some Hilbert space with a -action , or in other words, is equivariantly isomorphic with a sub- module of . Note that is the closure of under the norm inherited from where is any Hilbert space such that is isometrically embedded into . The following result on the embeddabiity is due to Mingo and Phillips ([6]).
Theorem 1.2
Let be a Hilbert module and assume that is countably generated as a Hilbert -module, that is, there is a countable set of elements of such that the right -linear span of is dense in . Assume furthermore that is compact. Then is embeddable.
When is the trivial singleton group, the above result was proved by Kasparov.
If the algebra is replaced by a von Neumann algebra for some Hilbert space and is a locally compact group with a strongly continuous unitary representation , one can define Hilbert von Neumann - module . The only difference is that is now a Hilbert von Neumann -module equipped with the natural locally convex strong operator topology, and that we replace the norm-continuity in (iii) of the above definition by a weaker continuity : namely, the continuity of (for fixed ) with respect to the locally convex topology of . In this case, we have a stronger version of the Theorem 1.2 (see [3] and [2], Theorem 4.3.5, page 99), namely without the condition of being countably generated and without the compactness of . It should be remarked here that the trivial Hilbert von Neumann module is defined to be the closure of with respect to the strong-operator-topology inherited from .
In Theorem 1.2, the assumption that is countably generated restricts the applicability of the result, since it is not always easy to check the property of being countably generated. However, under some special assumption on the - algebra , i.e. conditions on the group , the algebra and also on the nature of the action, it may be possible to prove the embedability for an arbitrary Hilbert - module. The aim of the present article is to give some such sufficient conditions.
2 Ergodic action and its implication
We say that the action of on a unital -algebra is ergodic if if and only if is a scalar multiplie of . There is a considerable amount of literature on ergodic action of compact groups, and we shall quote one interesting structure theorem which will be useful for us.
Proposition 2.1
*Let be a compact group acting ergodically on a unital -algebra Then there is a set of elements of , where is the set of equivalence classes of irreducible representations of , is the dimension of the irreducible representation space denoted by , is a natural number, such that the followings hold :
(i) There is a unique faithful -invariant state on , which is in fact a trace,
(ii) The linear span of is norm-dense in ,
(iii) is an orthonormal basis of ,
(iv) The action of coincides with the th irreducible representation of on the vector space spanned by for each fixed and ,
(v) , where denotes the Kronecker delta symbol. Thus, in particular, .*
The proof can be obtained by combining the results of [7],[4] and [1].
Let now , where is the unique invariant faithful trace described in Proposition 2.1. Let be the unitary in induced by the action of , that is, on the dense set where denotes the -action on . Denote also by the action on , which is the weak closure of in .
Let us now specialize to the case of a compact Lie group. If is such a group, with a basis of the Lie algebra given by , which has a strongly continuous action on a Banach space , we can consider the space of ‘smooth’ or -elements of , denoted by , consisting of all such that is . It is easy to prove that is dense in , and it is a -subalgebra if is a locally convex -algebra. Moreover, we equip with a family of seminorms , given by
[TABLE]
with the convention and where . The space is complete under this family of seminorms, and thus is a Frchet space. When is Hilbert space or a Hilbert module, we shall also consider a map given by essentially the same expression as that of , with replaced by , and the Hilbertian seminorms are given by
[TABLE]
with denoting the norm of the Hilbert space (or Hilbert module) .
More generally, if is a complete locally convex space given by a family of seminorms , then we can consider the smooth subspace and the maps as above, and make it a complete locally convex space with respect to a larger family of seminorms where
[TABLE]
In case is a von Neumann algebra equipped with the locally convex strong operator topology, the locally convex space is a topological -algebra, strongly dense in .
Lemma 2.2
[2]** Let be a compact Lie group acting ergodically on a unital -algebra Then as Frchet spaces.
*Proof :
*The fact that as sets is contained in Lemma 8.1.20 of [2] (page 200-201). We only prove that the identity map is a topological homeomorphism.
Since the trace is finite, the Frchet topology of is stronger than that of . This implies that the identity map , viewed as a linear map from the Frchet space to the Frchet space is closable, hence continuous. This completes the proof that the two Frchet topologies on are equivalent, i.e. as topological spaces.
Lemma 2.3
Let be a (not necessarily separable) Hilbert space with a unitary representation of , and let us consider the Frchet modules and corresponding to the action . Let be an element of such that is continuous in the operator-norm topology. Then actually belongs to .
*Proof :-
*We shall denote by () the -norm coming from the trace on . The identity of will also be viewed as a unit vector in . Fix an orthonormal basis of (which need not be separable), with each . Fix satisfying the hytothesis of the lemma. Since is separable, say with an orthonormal basis given by , we can find, for each , a counteble subset of such that for all . Denoting by the countable set , we have , for all . Write . Denote by the element in given by , where denotes the orthogonal projection onto the linear span of . It is clear that as . Now, for a complex-valued function on and an element , denote by the element , where stands for the normalised Haar measure on and the integral is convergent in the strong-operator topology. We claim that it is enough to prove that for all . Let us first prove this claim. Since is norm-continuous, given , we can find a nonempty open subset of such that for all , and then choose with , and . It is easy to see that . Thus, is the operator-norm limit of a sequence of elements of the form , which proves the claim.
Let us now complete the proof of the lemma by showing that indeed belongs to for every . To this end, first observe that belongs to for all . Moreover, since for all and , it is clear that as . Since each belongs to , for proving it is enough to prove that in the topology of , i.e. in the norm-topology of . We shall prove that in the Frchet topology of , which will prove that it converges to [math] also in the topology of
To this end, first note that for , we have
[TABLE]
hence . Moreover, (since we have ). From this, we have
[TABLE]
where . Let us now fix an ordered -tuple ( nonnegative integer), and let denote the maximum of where varies over all (including the empty set) ordered subsets of . Let us abbreviate and by and respectively, for . Note that
[TABLE]
Using this as well as the Leibniz formula (with varying over all ordered substes of ), we have the following :
[TABLE]
since the number of ordered subsets of is and it is clear from the definition of that for all . We also have as . This proves in the topology of , thereby completing the proof of the lemma.
3 Main results on equivariant embedding of Hilbert modules
Let be a module, where and are as in the previous section, i.e. is a compact Lie group acting ergodically on the algebra . In this final section, we shall prove that any such is embeddable.
Lemma 3.1
We can find a Hilbert space , a strongly continuous unitary representation and a -linear isometry , such that , and moreover, the complex linear span of elements of the form where and is dense in .
*Proof :
*The proof of this result is adapted from [3] and [2], Theorem 4.3.5 (page 99-101). We shall give only a brief sketch of the arguments involved, omitting the details. We consider first the formal vector space (say ) spanned by symbols , with and , and define a semi-inner product on this formal vector space by setting
[TABLE]
where denotes the -valued inner product on . By extending this semi-inner product by linearity and then taking quotient by the subspace (say ) consisting of elements of zero norm we get a pre-Hilbert space, and its completion under the pre-inner product is denoted by . We also define by setting
[TABLE]
where represents the equivalence class of in . That it is an isometry is verified by straightforward calculations. Next, we define on by
[TABLE]
and verify that it is indeed an isometry, and since its range clearly contains a total subset, extends to a unitary on . Furthermore, and (where is the identity of ) on ,and hence on the whole of The strong continuity of is also easy to see. Indeed, it is enough to prove that is continuous for any of the form , But and we have, By assumption in the norm topology of , so as . Furthermore, is continuous. This completes the proof of strong continuity of .
In view of the above result, we assume without loss of genetrality that (with the natural Hilbert module structure inherited from that of ), and . Consider the strong operator closure of of in . It is a Hilbert von Neumann module (where is the weak closure of in ) . Moreover, the -action can be extended to the whole of , and denoted again by . Clearly, this action leaves invariant, hence is a Hilbert von Neumann - module. Let us recall that by we denote the locally convex space of elements in such that is in the strong operator topology of .
Theorem 3.2
*There exist a Hilbert space , a unitary representation of in and an isometry from to such that
(i) is equivariant in the sense that for all ;
(ii) for all .
*Proof :
*The statement (i) is contained in the Theorem 4.3.5 of [2] (page 99). For proving (ii), we note that (w.r.t. the action ) is mapped by into (w.r.t. the action ), and moreover, for , is norm-continuous since is so and is isometry. Thus, (ii) follows from Lemma 2.3.
It follows from the above theorem that can be equivariantly embedded in the trivial module . In particular, we have that
Theorem 3.3
If a compact Lie group has an ergodic action on a -algebra , then every module is embeddable.
Acknowledgement : The author would like to thank the anonymous referee who pointed out a crucial mistake in the earlier version, which has led to substantial revision of the paper.
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